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3 years ago

A kilometer is ___as large as a picometer

Mathematics

2 answers:

Nataly_w [17]3 years ago

4 0

Answer:

Step-by-step explanation:

To find the answer divide a 1 kilometer by x amount of picometers.

K= x of p

K = 1000000000000000

or in short text

=1e+15

shepuryov [24]3 years ago

3 0

Answer:

1.0E+15

Step-by-step explanation:

im sure this is right

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What transformation to the graph occurs when f(x) = x^2 is changed to f(x) = 3(x-2)^2?

miskamm [114]

Answer:

Step-by-step explanation:

The -2 in the parentheses moves the graph horizontally 2 units to the right.

The 3 then stretches this graph vertically by a factor 3.

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A pet store 145 bags of beef flavored dog food and 263 bag of chesse flavored dog food how many bags of dog food where sold

Kazeer [188]

Answer:

408 bags of dog food

Step-by-step explanation:

The question asks for the total bags of dog food. Because they give you two existing values expressing how much dog food of each type there is, all you must do is add them together. 145 + 263 = 408

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3 years ago

A membership to LA Fitness is on sale for $ 112 50. That represents

RSB [31]

Answer:

Step-by-step explanation:

let the original price be x

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3 years ago

I need the answer for this exact question

denis23 [38]

Answer:

$y=\frac{7}{2}x-20$

Step-by-step explanation:

Let the equation of the line be $y-y_1=m(x-x_1)$ where, 'm' is its slope and $(x_1,y_1)$ is a point on it.

Given:

The equation of a known line is:

$y=-\frac{2}{7}x+9$

A point on the unknown line is:

$(x_1,y_1)=(4,-6)$

Both the lines are perpendicular to each other.

Now, the slope of the known line is given by the coefficient of 'x'. Therefore, the slope of the known line is $m_1=-\frac{2}{7}$

When two lines are perpendicular, the product of their slopes is equal to -1.

Therefore,

$m\cdot m_1=-1\\m=-\frac{1}{m_1}\\m=-\frac{1}{\frac{-2}{7} }=\frac{7}{2}$

Therefore, the equation of the unknown line is determined by plugging in all the given values. This gives,

$y-(-6))=\frac{7}{2}(x-4)\\y+6=\frac{7}{2}x-14\\y=\frac{7}{2}x-14-6\\\\y=\frac{7}{2}x-20$

The equation of a line perpendicular to the given line and passing through (4, -6) is $y=\frac{7}{2}x-20$ .

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3 years ago

What are the coordinates of the pre-image of N' if it was reflected across the y-axis, and N' has coordinates (3, -1)?

kirill115 [55]

I believe it is (-3,-1)

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3 years ago

Read 2 more answers