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Maksim231197 [3]
3 years ago
9

1. Find the sum of the measures of the interior angles of a convex 11-gon.

Mathematics
1 answer:
OleMash [197]3 years ago
3 0

Answer:

The measure of the sum of interior angles of a 11-gon is 1620^{o}.

Each interior angle is approximately 147.273^{o}.

Step-by-step explanation:

A convex polygon has the measure of each interior angles to be less than 180^{o}.

But,

sum of interior angles of polygon = (n - 2) x 180^{o}

where n is the number of sides of the polygon.

For a convex 11-gon, we have;

sum of angles of a 11-gon = (11 - 2) x 180^{o}

                                         = 9 x 180^{o}

                                         = 1620^{o}

Sum of angles of a 11-gon = 1620^{o}

To check: convex polygons' interior angles are less than 180^{o}.

so that,

each interior angle of 11-gon = \frac{1620}{11}

                                        = 147.273^{o}

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