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MArishka [77]
3 years ago
11

Which of the following are solutions to the inequality -7x+14>-3x-6? Select all that apply.

Mathematics
2 answers:
EastWind [94]3 years ago
8 0

Answer:

All real numbers less than 5 satisfy the inequality. The set of solutions of the inequality is the interval \left(-\infty \:,\:5\right).

Therefore, -10, -5, -3, 0, 3 are all valid solutions.

Step-by-step explanation:

Solving an inequality means finding all of its solutions. A solution of an inequality is a number which when substituted for the variable makes the inequality a true statement.

To find all the solutions for the inequality -7x+14>\:-3x-6 you must:

\mathrm{Subtract\:}14\mathrm{\:from\:both\:sides}\\-7x+14-14>-3x-6-14

\mathrm{Simplify}\\-7x>-3x-20

\mathrm{Add\:}3x\mathrm{\:to\:both\:sides}\\-7x+3x>-3x-20+3x

\mathrm{Simplify}\\-4x>-20

\mathrm{Multiply\:both\:sides\:by\:-1\:\left(reverse\:the\:inequality\right)}\\\left(-4x\right)\left(-1\right)

\mathrm{Simplify}\\\\4x

All real numbers less than 5 satisfy the inequality. The set of solutions of the inequality is the interval \left(-\infty \:,\:5\right).

Therefore, -10, -5, -3, 0, 3 are all valid solutions.

JulijaS [17]3 years ago
6 0

-7x+14>-3x-6

add 7x to each side

14> 4x-6

add 6 to each side

20>4x

divide by 4

5>x

x<5

solutions

3,0,-3,-5,-10

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Assignment The operation teeter is defined on the set T= { 2, 3, 5, 7 } by x teeter y=[x+y+xy) mod.8 a - Construct mod.8 table f
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Explanation:

For this exercise we use Newton's relation for rotation

        Σ τ  = I α

In this exercise the mass of the child is m = 28.8, assuming x = 1.5 m, the force applied by the man is F = 180N

we will assume that the counterclockwise turns are positive.

case a

        tau_net = m g x - F x2

         tau_nett = -28.8 9.8 1.5 + 180 1

        tau_net = -243.36 N m

in this case the man's force is downward and the system rotates clockwise

case b

2 force clockwise, the direction of

the force is up

         tau_nett = -28.8 9.8 1.5 - 180 2

         tau_net = 783.36 N / m

in case the force is applied upwards

3) counterclockwise

       tau_nett = -28.8 9.8 1.5 + 180 2

        tau_net = -63.36 N m

system rotates clockwise

case c

2 schedule

tau_nett = -28.8 9.8 1.5 - 180 3

tau _net = - 963.36 N m

3 counterclockwise

      tau_nett = -28.8 9.8 1.5 + 180 3

      tau_net = 116.64 Nm

the sitam rotated counterclockwise

<h3><u><em>Cr: moya1316</em></u></h3>
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