Can anyone answer -4(3-x)-7x and show the work !

A spinner is divided into 8 section of equal size. The sections are numbered 1 through 8. Use this information to determine the

olga_2 [115]

1) 1/8

2) 1/2

Step-by-step explanation:

1)

First of all, we notice that the spinner is divided into 8 sections of equal size.

So the number of sections is

n = 8

Secondly, we note that each section has the same size: this means that the probability of the spinner landing on each section is the same.

The probabilty of a certain event A to occur is given by

$p(A)=\frac{a}{n}$

where

a is the number of successfull outcomes (in which A occurs)

n is the total number of possible outcomes

Here we want to find

$p(7)$ = probability that the spinner lands on section 7

Here we have:

$a=1$ (only 1 outcome is successfull: the one in which the spinner lands on section 7)

$n=8$

Therefore, the probability is

$p(7)=\frac{1}{8}$

2)

Here we want to find the probability that the spinner lands on an even numbered section.

As before, the total number of possible outcomes his:

$n=8$

which corresponds to: 1, 2, 3, 4, 5, 6, 7, 8

The even-numbered sections are:

2, 4, 6, 8

So, the number of successfull outcomes is

$a=4$

Because there are only 4 even-numbered sections.

Therefore, the probability that the spinner lands on an even numbered section is:

$p(e)=\frac{a}{n}=\frac{4}{8}=\frac{1}{2}$

8 0

3 years ago

Please can you simplify -x+2z+x+2y

slavikrds [6]

Answer:

2y + 2z

Step-by-step explanation:

-x + 2z + x + 2y

= (-1 + 1)x + 2y + 2z

= 2y + 2z

Hope this helped!

3 0

3 years ago

In a football or soccer game, you have 22 players, from both teams, in the field. what is the probability of having at least any

Tamiku [17]

We can solve this problem using complementary events. Two events are said to be complementary if one negates the other, i.e. E and F are complementary if

$E \cap F = \emptyset,\quad E \cup F = \Omega$

where $\Omega$ is the whole sample space.

This implies that

$P(E) + P(F) = P(\Omega)=1 \implies P(E) = 1-P(F)$

So, let's compute the probability that all 22 footballer were born on different days.

The first footballer can be born on any day, since we have no restrictions so far. Since we're using numbers from 1 to 365 to represent days, let's say that the first footballer was born on the day $d_1$ .

The second footballer can be born on any other day, so he has 364 possible birthdays:

$d_2 \in \{1,2,3,\ldots 365\} \setminus \{d_1\}$

the probability for the first two footballers to be born on two different days is thus

$1 \cdot \dfrac{364}{365} = \dfrac{364}{365}$

Similarly, the third footballer can be born on any day, except $d_1$ and $d_2$ :

$d_3 \in \{1,2,3,\ldots 365\} \setminus \{d_1,d_2\}$

so, the probability for the first three footballers to be born on three different days is

$1 \cdot \dfrac{364}{365} \cdot \dfrac{363}{365}$

And so on. With each new footballer we include, we have less and less options out of the 365 days, since more and more days will be already occupied by another footballer, and we can't have two players born on the same day.

The probability of all 22 footballers being born on 22 different days is thus

$\dfrac{364\cdot 363 \cdot \ldots \cdot (365-21)}{365^{21}}$

So, the probability that at least two footballers are born on the same day is

$1-\dfrac{364\cdot 363 \cdot \ldots \cdot (365-21)}{365^{21}}$

since the two events are complementary.

8 0

3 years ago

Plz plz plz help me with this

erica [24]

This question wants you to find a common denominator for the fractions.
This means finding the LCM, least common multiple, for 21 and 9.
This can be done by listing the multiples for each number until they meet at a common one.

9:
9
18
27
36
45
54
63

21:
21
42
63

This means the LCM of 21 and 9 is 63.
So the lowest possible common denominator is 63.

21 • 3 = 63
So you have to multiply the numerator of 2/21 by 3 as well.
2 • 3 = 6
2/21 = 6/63

Now do the same for 1/9.
9 • 7 = 63
Multiply the numerator, 1, by 7.
1 • 7 = 7
1/9 = 7/63

So in the first blanks, you would put 6/63 for what 2/21 is equal to and 7/63 for what 1/9 is equal to.

7/63 is greater than 6/63.
7/63 > 6/63
That means 1/9 > 2/21
So 2/21 < 1/9 is the answer to the last blank.

Hope this helps!

6 0

3 years ago

2. y = 5x2 + 10x – 3

Mice21 [21]

Answer:

x= -7/10 or x= -0.7 , y= 7

Step-by-step explanation:

Find the x-intercept: Find the y-intercept:

y= 5×2+10x-3 y= 5×2+10x-3

0=10+10x-3 y= 5×2+10×0-3

0=7+10x y= 7

-10x=7

x=-7/10

8 0

3 years ago