2 years ago

HELPPPP PLEASEEEeeeeeee

Mathematics

2 answers:

sergij07 [2.7K]2 years ago

5 0

Answer:

I think it is non proportional

BabaBlast [244]2 years ago

5 0

Answer:

non-proportional

Step-by-step explanation:

it isn't linear

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What are the roots of x in -10x2 + 12x − 9 = 0?

hoa [83]

Answer:

$x_1=\frac{3(2+i\sqrt{6})}{10}$

$x_2=\frac{3(2-i\sqrt{6})}{10}$

Step-by-step explanation:

Use the Quadratic formula:

$x=\frac{-b\±\sqrt{b^2-4ac}}{2a}$

You can identify that, in this case:

$a=-10\\b=12\\c=-9$

Now you need to substitute these values into the formula:

$x=\frac{-12\±\sqrt{12^2-4(-10)(-9)}}{2(-10)}$

$x=\frac{-12\±\sqrt{-216}}{-20}$

Remember that:

$i=\sqrt{-1}$

Therefore,rewriting and simplifying, you get:

$x=\frac{-12\±6i\sqrt{6}}{-20}$

$x=\frac{-6(2\±i\sqrt{6})}{-2(10)}$

$x=\frac{3(2\±i\sqrt{6})}{10}$

Then, you get the following roots:

$x_1=\frac{3(2+i\sqrt{6})}{10}$

$x_2=\frac{3(2-i\sqrt{6})}{10}$

6 0

2 years ago

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san4es73 [151]

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2 years ago

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Answer:

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Step-by-step explanation:

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If a = 5 in the right triangle what is the value of b and c

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Answer:

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Step-by-step explanation:

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2 years ago

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Answer:

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Step-by-step explanation:

y = mx + b

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then 3 = (-1/3)6 + b

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so y = -1/3x + 5

5 0

1 year ago