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Sati [7]
3 years ago
12

Who can solve this for me real quick?

Mathematics
1 answer:
max2010maxim [7]3 years ago
3 0

Answer:

Vertex (-3, -3)

Step-by-step explanation:

Highest or lowest point lying on the graph of a parabola is said to be the Vertex of a parabola.

By this definition, point P (lowest point) is the vertex of the given parabola.

Coordinates of the Vertex are (-3, -3).

Therefore, Vertex (-3, -3) is the answer.

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A restaurant uses 4375 pounds of cheese for every 8 3/4 pizzas atvrgis rate how many pounds of cheese are used per pizza
Arlecino [84]
34 pounds that’s the answer
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What is the perimeter of a rectangular garden with a width of 24 feet and a diagonal of 40 feet?
elena55 [62]
Drawing it out, as seen, using the Pythagorean theorem we get that w^2+l^2 (with w=width and l=length)=diagonal^2=24^2+l^2=40^2. Subtracting 24^2 from both sides, we get 40^2-24^2=l^2=1024. Square rooting both sides, we get l=32. Since the perimeter is 2w+2l, we get 32*2+24*2=64+48=112

8 0
3 years ago
At an airport, 76% of recent flights have arrived on time. A sample of 11 flights is studied. Find the probability that no more
I am Lyosha [343]

Answer:

The probability is  P( X \le 4 ) = 0.0054

Step-by-step explanation:

From the question we are told that

   The percentage that are on time is  p =  0.76

   The  sample size is n =  11

   

Generally the percentage that are not on time is

     q =  1- p

     q =  1-  0.76

     q = 0.24

The  probability that no more than 4 of them were on time is mathematically represented as

        P( X \le 4 ) =  P(1 ) +  P(2) + P(3) +  P(4)

=>     P( X \le 4 ) =  \left n } \atop {}} \right.C_1 p^{1}  q^{n- 1} +   \left n } \atop {}} \right.C_2p^{2}  q^{n- 2} +  \left n } \atop {}} \right.C_3 p^{3}  q^{n- 3}  +  \left n } \atop {}} \right.C_4 p^{4}  q^{n- 4}

P( X \le 4 ) =  \left 11 } \atop {}} \right.C_1 p^{1}  q^{11- 1} +   \left 11 } \atop {}} \right.C_2p^{2}  q^{11- 2} +  \left 11 } \atop {}} \right.C_3 p^{3}  q^{11- 3}  +  \left 11 } \atop {}} \right.C_4 p^{4}  q^{11- 4}

P( X \le 4 ) =  \left 11 } \atop {}} \right.C_1 p^{1}  q^{10} +   \left 11 } \atop {}} \right.C_2p^{2}  q^{9} +  \left 11 } \atop {}} \right.C_3 p^{3}  q^{8}  +  \left 11 } \atop {}} \right.C_4 p^{4}  q^{7}

= \frac{11! }{ 10! 1!}  (0.76)^{1}  (0.24)^{10} +   \frac{11!}{9! 2!}  (0.76)^2 (0.24)^{9} + \frac{11!}{8! 3!}  (0.76)^{3}  (0.24)^{8}  + \frac{11!}{7!4!}  (0.76)^{4}  (0.24)^{7}

P( X \le 4 ) = 0.0054

4 0
3 years ago
By what percent will the fraction change if its numerator is increased by 25% and its denominator is increased by 20%? please an
d1i1m1o1n [39]
<h2>Answer:</h2><h2>The new fraction will chnage by 1.25 : 1.2 ratio, (i.e) = 1.04 %</h2>

Step-by-step explanation:

Let the fraction be represented as \frac{x}{y} where x is the numerator and y is the denominator

Given that numerator will increase by 25 %, = 25% x

   = 0.25 x

Given that denominator will increase by 20 %, = 20% y

   = 0.2 y

The new fraction becomes  = \frac{x + 0.25 x}{y + 0.2 y}

= \frac{1.25 x}{1.2 y}

= (\frac{1.25}{1.2} ) \frac{x}{y}

The new fraction will chnage by 1.25 : 1.2 ratio, (i.e) = 1.04 %

5 0
3 years ago
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