Exterior angle c = the sun of the two opposite interior angles a and b.
10x -23 = 5x -17 + 7x -26
Combine the right side:
10x -23 = 12x -43
Add 43 to both sides:
10x +20 = 12x
Subtract 10x from both sides:
20 = 2x
Divide both sides by 2
X = 10
Now you have x replace it in the equation for A:
A = 5x -27 = 5(10) -27 = 50-27 = 23
Angle A = 23 degrees.
Answer:
74.8
Step-by-step explanation:
hope im right!
Answer:
16225
Step-by-step explanation:
You need to multiply
1: I can’t see one it’s cut out sorry :(
2:go down four horrizontal for each line making a rhombus
3: 3a:true 3b:true 3c:false 3D: false
4.PART A: Draw a square in the middle.
4. PART B: Say there are four right angles
5: Line, point, ray, line segment
6. There are 2 acute and 1 right
7. A B C
8: 1/4 1/6 1/8
9: 9a 9c and 9d
10: square and polygons first, then triangles because they have 4 sides while a triangle has 3
10 PART B: rectangles second, then the pentagons are third, the parallelogram is first, then the triangles because a rectangle has all right angles
11: she drew a square!
12: polygons without right angles
13: I can’t draw on your paper just draw three lines in the trapezoid
13: a c and d
1. A quadratic equation has the following form: ax²+bx+c.
2. The leading coefficient is the number that is attached to the variable with the highest exponent. Then, the "a" is the leading coefficient of the quadratic equation.
3. The problem says that the leading coefficient is 1 (a=1) and the roots of the quadratic equation are 5 and -3. Then, you have:
(x-5)(x+3)=0
4. When you apply the distributive property, you obtain:
x²+3x-5x-15=0
x²-2x-15=0
5. Therefore, the answer is:
x²-2x-15=0
