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Korolek [52]
3 years ago
9

Please help me with this

Mathematics
1 answer:
Free_Kalibri [48]3 years ago
6 0

Answer:

See photo

Step-by-step explanation:

We can fill out many of these pretty easily. Look at the picture below. (Black numbers represent what information they already gave us)

Now, for the actual math.

If a total of 46 seventh-graders were surveyed and 28 seventh-graders spent more than an hour on their phone, then that means that there would have to be 46-28=18 students that spend less than an hour on their phone.

If there are 43 total students that spend more than an hour on their phone, and 28 of those are seventh-graders, then there are 43-28=15 eighth-graders that spend more than an hour on their phone

Then, if there are 27 total eighth-graders, and 15 of those spend more than an hour, then that leaves 27-15=12 eighth-graders that spend less than an hour on their phone.

Lastly, figure out the total numbers.

There are 18 seventh-graders and 12 eighth-graders that spend less than an hour on their phone, so there is a total of 18+12 = 30 students that spend less than an hour on their phone.

There are a total of 46 seventh-graders and 27 eighth-graders that were surveyed, which is a total of 73 students surveyed.

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Answer:

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Step-by-step explanation:

Ok, sabemos que:

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Queremos calcular:

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Tambien sabemos que 4 = 2*2

Entonces:

4^x + 4^{-x} = (2*2)^x + (2*2)^{-x}

y sabemos que 2*2 = 2^2

Entonces:

4^x + 4^{-x} = (2*2)^x + (2*2)^{-x} = (2^2)^x + (2^2)^{-x}

y ahora podemos usar la relación:

(a^n)^m = (a^m)^n = a^{m*n}

entonces:

(2^2)^x + (2^2)^{-x} = (2^x)^2 + (2^{-x})^2

Ahora podemos completar cuadrados sumando y restando el termino:

2*(2^x)*(2^{-x})

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Entonces de momento tenemos que:

4^x + 4^{-x} = (2^x + 2^{-x})^2 - 2*(2^x)*(2^{-x})

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Y tambien podemos usar la propiedad:

a^n*a^m = a^{n + m}

en el termino de la derecha.

Asi tendremos:

(2^x + 2^{-x})^2 - 2*(2^x)*(2^{-x}) = (3)^2 - 2*2^{x + (-x)}  = 9 - 2 = 7

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