What is 37.81 to the nearest tenth?

So i need to know how to do this and I need some help understanding this

NikAS [45]

What do you need help understanding?

5 0

3 years ago

Hector drew three rectangles to show the letter H on his notebook. Use the rectangles to find the area of the letter he drew.

Luba_88 [7]

The area of the H is 86

7 0

3 years ago

What is the perimeter of triangle ABC ? 11 units 14 units 16 units 20 units Coordinate graph showing triangle A B C. Triangle A

professor190 [17]

Answer:

The perimeter is equal to $16\ units$

Step-by-step explanation:

we have that

$A(-1,1),B(2,5),C(5,1)$

The perimeter of triangle ABC is equal to

$P=AB+BC+AC$

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

step 1

Find the distance AB

$A(-1,1),B(2,5)$

$AB=\sqrt{(5-1)^{2}+(2+1)^{2}}$

$AB=\sqrt{(4)^{2}+(3)^{2}}$

$AB=\sqrt{25}$

$AB=5\ units$

step 2

Find the distance BC

$B(2,5),C(5,1)$

$BC=\sqrt{(1-5)^{2}+(5-2)^{2}}$

$BC=\sqrt{(-4)^{2}+(3)^{2}}$

$BC=\sqrt{25}$

$BC=5\ units$

step 3

Find the distance AC

$A(-1,1),C(5,1)$

$AC=\sqrt{(1-1)^{2}+(5+1)^{2}}$

$AC=\sqrt{(0)^{2}+(6)^{2}}$

$AC=\sqrt{36}$

$AC=6\ units$

step 4

Find the perimeter

$P=5+5+6=16\ units$

4 0

4 years ago

Read 2 more answers

The ratio table below shows the number of eggs per omelet.

docker41 [41]

The answer if 4. The number of eggs to omlets is linear meaning they all change in a pattern. The number of eggs are doubeling while the number of omlets are going up by one. So the answer would be 4

3 0

4 years ago

Read 2 more answers

Use the quadratic regression to find the equation for the parabola going through these 3 points (-5, 161) (-2, 29) (6, 205)

Rama09 [41]

Answer:

The equation of the parabola is y = 6 $x^{2}$ -2b+1

Step-by-step explanation:

First we write a quadratic equation of parabola as y = a $x^{2}$ +bx+c

Now it is given in the question that parabola passes through three points (-5,161),(-2,29),(6,205).

To find the equation we have to get the value of a,b & c.

Now we form three equations to find the value of a,b,c.

We put the value (-5,161) in the equation

161 = a×25+b×(-5)+c

161 = 25a-5b+c----------(1)

Now we put (-2,29) in the equation

29 = a×4+b×(-2)+c

29 = 4a-2b+c---------(2)

Again we put (6,205) in the equation

205 = a×36+6b+c------------(3)

Now we subtract equation (1) from (2)

161-29 = 25a-4a-5b-(-2b)+c-c

132 = 21a-5b+2b

132 = 21a-3b

132 = 3(7a-b)

44 = 7a-b---------(4)

Now we subtract equation (2) from (3)

205-29 = 36a-4a+6b-(-2b)+c-c

176 = 32a+6b+2b

176 = 32a+8b

176 = 8(4a+b)

22 = 4a+b------------(5)

Now we add equation (5) and (4)

44+22 = 7a+4a-b+b

66 = 11a

a = 6

Now we put the value a in equation (4)

44 = 7×6-b

44 = 42-b

44-42 = -b

2 = (-b)

b = (-2)

Now we put the value of a and b in equation number (2)

29 = 4×6-2(-2)+c

29 = 24+4+c

29 = 28+c

c = 29-28

c =1

Finally we put the value of a,b,c in the quadratic equation

y = 6 $x^{2}$ +(-2)x+1

y = 6 $x^{2}$ -2+1

This is the final answer.

6 0

3 years ago