Question

What is the perimeter of triangle ABC ? 11 units 14 units 16 units 20 units Coordinate graph showing triangle A B C. Triangle A B C has vertex A at negative 1 comma 1, vertex B at 2 comma 5, and vertex C at 5 comma 1.

Answer 1

Answer:

The perimeter is equal to $16\ units$

Step-by-step explanation:

we have that

$A(-1,1),B(2,5),C(5,1)$

The perimeter of triangle ABC is equal to

$P=AB+BC+AC$

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

step 1

Find the distance AB

$A(-1,1),B(2,5)$

$AB=\sqrt{(5-1)^{2}+(2+1)^{2}}$

$AB=\sqrt{(4)^{2}+(3)^{2}}$

$AB=\sqrt{25}$

$AB=5\ units$

step 2

Find the distance BC

$B(2,5),C(5,1)$

$BC=\sqrt{(1-5)^{2}+(5-2)^{2}}$

$BC=\sqrt{(-4)^{2}+(3)^{2}}$

$BC=\sqrt{25}$

$BC=5\ units$

step 3

Find the distance AC

$A(-1,1),C(5,1)$

$AC=\sqrt{(1-1)^{2}+(5+1)^{2}}$

$AC=\sqrt{(0)^{2}+(6)^{2}}$

$AC=\sqrt{36}$

$AC=6\ units$

step 4

Find the perimeter

$P=5+5+6=16\ units$

Answer 2

Answer:

The answer is 16 untis

Step-by-step explanation: