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3 years ago

Simplify ; 7a+4b+7a-3b

Mathematics

2 answers:

Afina-wow [57]3 years ago

8 0

14a+b is the correct answer

LuckyWell [14K]3 years ago

8 0

The answer is 14a+b
You need to add the like terms together:
7a+7a=14a
4b-3b=b (1b is the same as "b" but 1b is sloppy)

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Calculate the area of this trapezium.<br> 7.9 cm<br> 6.2 cm<br> 10.8 cm

cestrela7 [59]

Answer:

A = 57.97 cm²

Step-by-step explanation:

The area (A) of a trapezium is calculated as

A = $\frac{1}{2}$ h (a + b)

where h is the perpendicular height and a, b the parallel bases

Here h = 6.2, a = 10.8 and b = 7.9, thus

A = $\frac{1}{2}$ × 6.2 × (10.8 + 7.9) = 3.1 × 18.7 = 57.97 cm²

5 0

3 years ago

Which two expressions are equivalent to 20 + 48 ?

monitta

Answer:

A and D

Step-by-step explanation:

2(10)=20

2(24)=48

20+48

4(5)=20

4(12)=48

20+48

i hope this helps!

3 0

2 years ago

(b) The area of a rectangular painting is 7719 cm2.

Nataliya [291]

Given:

The area of a rectangular painting is 7719 cm²
Width of painting = 83cm

To Find?

Length of painting.

Solution:

Let length of painting be x cm

Using formula:

Area of rectangle = L × B

Where,

Length = x cm
Breadth = 73 cm

→ 7719 = x × 83

→ x = 7719/83

→ x = 93 cm

Hence,

Length of painting is 93cm

6 0

2 years ago

Read 2 more answers

We are given a sequence of five non-zero numbers, where the sum of each term and its neighboring terms is 15 or 25. Find the sum

PSYCHO15rus [73]

We have a sequence that meets the given criteria, and with that information, we want to get the sum of all the terms in the sequence.

We will see that the sum tends to infinity.

So we have 5 terms;

A, B, C, D, E.

We know that the sum of each term and its neighboring terms is 15 or 25.

then:

A + B + C = 15 or 25
B + C + D = 15 or 25
C + D + E = 15 or 25

Now, we want to find the sum of all the terms in the sequence (not only the 5 given).

Then let's assume we write the sum of infinite terms as:

$a_1 + a_2 + a_3 + a_4 + a_5 + a_6 + ...$

Now we group that sum in pairs of 3 consecutive terms, so we get:

$(a_1 + a_2 + a_3) + (a_4 + a_5 + a_6) + ...$

So we will have a sum of infinite of these, and each one of these is equal to 15 or 25 (both positive numbers). So when we sum that infinite times (even if we always have the smaller number, 15) the sum will tend to be infinite.

Then we have:

$(a_1 + a_2 + a_3) + (a_4 + a_5 + a_6) + ... \to \infty$

If you want to learn more, you can read:

brainly.com/question/21885715

3 0

2 years ago

Mr. Brady is using a coordinate plane to design a treasure hunt for his students. The hunt begins at the flagpole. The first clu

dmitriy555 [2]

Answer:

The figure is attached and the total distance is 1031 feet.

Step-by-step explanation:

The graph is indicated in the attached figure.

For calculation of distance consider following

Point Flagpole is (0,0)

Point Clue1 is (0,5)

Point Clue2 is (6,0)

Point Clue3 is (0,-5)

So the distance is calculated as follows

$d_{T}=[d_{FP\ to\ Clue1}+d_{Clue1\ to\ Clue2}+d_{Clue2\ to\ Clue3}]*distance\ per\ unit\\d_{T}=[\sqrt{(Clue1_x-FP_x)^2+(Clue1_y-FP_y)^2}+\sqrt{(Clue2_x-Clue1_x)^2+(Clue2_y-Clue1_y)^2}+\sqrt{(Clue3_x-Clue2_x)^2+(Clue3_y-Clue2_y)^2}]**distance\ per\ unit\\$ Substituting the values

$d_{T}=[\sqrt{(0-0)^2+(5-0)^2}+\sqrt{(6-0)^2+(0-5)^2}+\sqrt{(0-6)^2+(-5-0)^2}]*50 \text{ feet}\\d_{T}=[\sqrt{(0)^2+(5)^2}+\sqrt{(6)^2+(-5)^2}+\sqrt{(-6)^2+(-5)^2}]*50 \text{ feet}\\d_{T}=[\sqrt{0+25}+\sqrt{36+25}+\sqrt{36+25}]*50 \text{ feet}\\d_{T}=[\sqrt{25}+\sqrt{61}+\sqrt{61}]*50 \text{ feet}\\d_{T}=[5+7.81+7.81]*50 \text{ feet}\\d_{T}=[20.62]*50 \text{ feet}\\d_{T}=1031 \text{ feet}\\$

So the total distance travelled is 1031 feet.

4 0

3 years ago