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ExtremeBDS [4]
3 years ago
8

These are numbers with more than two factors. *

Mathematics
2 answers:
vagabundo [1.1K]3 years ago
8 0

Step-by-step explanation:

composite number

please mark as brilliant

maxonik [38]3 years ago
4 0

Answer: A

Step-by-step explanation:

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Please help! I need the answer fast!
Lubov Fominskaja [6]

Answer:IS D PLEASE MARK ME

Step-by-step explanation:

7 0
3 years ago
Raju is cycling at a speed of 30km/h. He applies brakes and stops at a junction in 10s. Calculate the acceleration.
Sedbober [7]

Answer:

Acceleration = 3m/s²

Step-by-step explanation:

Here ,

Initial velocity = 30km/h

Final velocity = 0km/h

Time = 10s

Acceleration = ?

We know ,

A = v-u/t

or , A = 0-30/10

or, A = 30/10

A = 3m/s²

Therefore the acceleration is 3m/s²

7 0
3 years ago
What is the answer to this question
almond37 [142]

Answer:

C. 24 1/4

Step-by-step explanation:

You turn both the lowest and the highest values into improper fractions and subtract the numerators then turn it back into a mixed fraction.

7 0
3 years ago
Suppose that 40 percent of the drivers stopped at State Police checkpoints in Storrs on Spring Weekend show evidence of driving
lesantik [10]

Answer:

a) 0.778

b) 0.9222

c) 0.6826

d) 0.3174

e) 2 drivers

Step-by-step explanation:

Given:

Sample size, n = 5

P = 40% = 0.4

a) Probability that none of the drivers shows evidence of intoxication.

P(x=0) = ^nC_x P^x (1-P)^n^-^x

P(x=0) = ^5C_0  (0.4)^0 (1-0.4)^5^-^0

P(x=0) = ^5C_0 (0.4)^0 (0.60)^5

P(x=0) = 0.778

b) Probability that at least one of the drivers shows evidence of intoxication would be:

P(X ≥ 1) = 1 - P(X < 1)

= 1 - P(X = 0)

= 1 - ^5C_0 (0.4)^0 * (0.6)^5

= 1 - 0.0778

= 0.9222

c) The probability that at most two of the drivers show evidence of intoxication.

P(x≤2) = P(X = 0) + P(X = 1) + P(X = 2)

^5C_0  (0.4)^0  (0.6)^5 + ^5C_1  (0.4)^1  (0.6)^4 + ^5C_2  (0.4)^2  (0.6)^3

= 0.6826

d) Probability that more than two of the drivers show evidence of intoxication.

P(x>2) = 1 - P(X ≤ 2)

= 1 - [^5C_0  (0.4)^0  (0.6)^5 + ^5C_1  (0.4)^1  (0.6)^4 + ^5C_2 * (0.4)^2  (0.6)^3]

= 1 - 0.6826

= 0.3174

e) Expected number of intoxicated drivers.

To find this, use:

Sample size multiplied by sample proportion

n * p

= 5 * 0.40

= 2

Expected number of intoxicated drivers would be 2

7 0
3 years ago
How many squares to shade
slamgirl [31]
You got to shade five squares
6 0
3 years ago
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