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gulaghasi [49]
3 years ago
12

20. It takes Zach 15 minutes to walk 7 blocks to the swimming pool. 7 At this rate, how many blocks can he walk in one minute? C

ircle the letter of the correct answer. how do I do this step by step to solve it by myself ​
Mathematics
2 answers:
NISA [10]3 years ago
7 0

Answer:

Zach chose C as the correct answer

Andreas93 [3]3 years ago
6 0
Uh I think it would be 0.47

7 divided by 15 is 0.47, that’s the amount of miles divided by the number of minutes. I’m really sleep deprived so sorry if this answer is wrong 3
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erik drove 439.92 miles on 15.6 gallons of gas. To the nearest hundredth, how many miles could he drive on 39.7 gallons of gas?
Thepotemich [5.8K]
In the question it is already given that Eric drove for 439.92 miles on 15.6 gallons. It is required to find the distance traveled on 39.7 gallons of gas. Also we have to find the answer to the nearest hundredth.
Then,
In 15.6 gallons Eric can drive for a distance = 439.92 miles
In 39.7 gallons Eric can drive for a distance = [(439.92/15.6) * 39.7] miles
                                                                       = 1119.54 miles
So the total distance traveled by Eric is 1120 miles with 39.7 gallons of gas. The answer has been calculated to the nearest hundredth.
6 0
4 years ago
the area of a rectangle is 90 in2^. the ratio of the length to the width is 5:2. find the length and the width
-BARSIC- [3]

Length and width of rectangle is 15 inches and 6 inches respectively

<h3><u>Solution:</u></h3>

Given that area of a rectangle is 90 square inch

Ratio of length to the width = 5: 2.

Need to determine length and width of rectangle.  

As ratio of length to the width is 5 : 2

Lets assume length of rectangle = 5x inches and width of rectangle = 2x inches.

<em><u>The formula for area of rectangle is given as:</u></em>

\text { Area of rectangle }=\text { length of rectangle } \times \text { width of rectangle}

Substituting the given value of area of rectangle and assumed value of length and width of rectangle we get:

\begin{array}{l}{90=5 x \times 2 x} \\\\ {=>90=10 x^{2}}\end{array}

On solving the above expression for x we get

\begin{array}{l}{=>\frac{90}{10}=x^{2}} \\\\ {=>x^{2}=9} \\\\ {=>x=\sqrt{9}=3}\end{array}

\begin{array}{l}{\text { Length of rectangle }=5 \times x=5 \times 3=15 \text { inches }} \\\\ {\text { Width of rectangle }=2 \times} x=2 \times} 3=6 \text { inches }}\end{array}

Hence length and width of rectangle is 15 inches and 6 inches.

4 0
4 years ago
Ruben sees 14 wheels on a total of 6 bicycles and tricycles. How many bicycles and tricycles are there?
Rina8888 [55]
4 bicycles 2 tricycles 
4  (bicycles)times 2(number of wheels on each bicycle) = 8
2 (bike) time 3 (number of wheels on each) = 6
8+6=14 

5 0
3 years ago
Read 2 more answers
If Elisa gets an allowance of $35 per week and spends $10 of it on food and drink, $5 on entertainment and $5 on miscellaneous t
Maslowich

Answer:

15$

Step-by-step explanation:

35-10=25$

25-5=20$

20-5=15$

6 0
4 years ago
The weight of the chocolate and Hershey Kisses are normally distributed with a mean of 4.5338 G and a standard deviation of 0.10
Salsk061 [2.6K]

For the bell-shaped graph of the normal distribution of weights of Hershey kisses, the area under the curve is 1, the value of the median and mode both is 4.5338 G and the value of variance is 0.0108.

In the given question,

The weight of the chocolate and Hershey Kisses are normally distributed with a mean of 4.5338 G and a standard deviation of 0.1039 G.

We have to find the answer of many question we solve the question one by one.

From the question;

Mean(μ) = 4.5338 G

Standard Deviation(σ) = 0.1039 G

(a) We have to find for the bell-shaped graph of the normal distribution of weights of Hershey kisses what is the area under the curve.

As we know that when the mean is 0 and a standard deviation is 1 then it is known as normal distribution.

So area under the bell shaped curve will be

\int\limits^{\infty}_{-\infty} {f(x)} \, dx= 1

This shows that that the total area of under the curve.

(b) We have to find the median.

In the normal distribution mean, median both are same. So the value of median equal to the value of mean.

As we know that the value of mean is 4.5338 G.

So the value of median is also 4.5338 G.

(c) We have to find the mode.

In the normal distribution mean, mode both are same. So the value of mode equal to the value of mean.

As we know that the value of mean is 4.5338 G.

So the value of mode is also 4.5338 G.

(d) we have to find the value of variance.

The value of variance is equal to the square of standard deviation.

So Variance = (0.1039)^2

Variance = 0.0108

Hence, the value of variance is 0.0108.

To learn more about normally distribution link is here

brainly.com/question/15103234

#SPJ1

3 0
1 year ago
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