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3 years ago

What is the equation for a line that passes through the points (5,-4) and (-10,17

Mathematics

1 answer:

maria [59]3 years ago

7 0

Answer:

The equation of the line is 7 x +5 y = 15.

Step-by-step explanation:

Here the given points are ( 5, -4) & ( -10, 17) -

Equation of a line whose points are given such that

( $x_{1},y_{1}$ ) & ( $x_{2}, y_{2}$ )-

y - $y_{1}$ = $\frac{y_{2} - y_{1} }{x_{2} - x_{1}}$ ( x - $x_{1}$ )

i.e. y - (-4)= $\frac{17 - (-4)}{-10 - 5}$ ( x- 5)

y + 4 = $\frac{17 + 4}{ -15}$ ( x - 5)

y + 4 = $\frac{21}{-15}$ ( x - 5 )

( y + 4) = $\frac{7}{- 5}$ ( x - 5)

5 (y + 4 ) = - 7 (x - 5 )

5 y + 20 = -7 x + 35

7 x + 5 y = 15

Hence the equation of the required line whose passes trough the points ( 5, -4) & ( -10, 17) is 7 x + 5 y = 15.

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swat32

The correct answer is definitely C.

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3 years ago

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A quality analyst of a tennis racquet manufacturing plant investigates if the length of a junior's tennis racquet conforms to th

Burka [1]

Answer:

Confidence interval : $21.506$ to $24.493$

Step-by-step explanation:

A quality analyst selects twenty racquets and obtains the following lengths:

21, 25, 23, 22, 24, 21, 25, 21, 23, 26, 21, 24, 22, 24, 23, 21, 21, 26, 23, 24

So, sample size = n =20

Now we are supposed to find Construct a 99.9% confidence interval for the mean length of all the junior's tennis racquets manufactured at this plant.

Since n < 30

So we will use t-distribution

Confidence level = 99.9%

Significance level = α = 0.001

Now calculate the sample mean

X=21, 25, 23, 22, 24, 21, 25, 21, 23, 26, 21, 24, 22, 24, 23, 21, 21, 26, 23, 24

Sample mean = $\bar{x}=\frac{\sum x}{n}$

Sample mean = $\bar{x}=\frac{21+25+23+22+24+21+25+21+23+ 26+ 21+24+22+ 24+23+21+ 21+ 26+23+ 24}{20}$

Sample mean = $\bar{x}=23$

Sample standard deviation = $\sqrt{\frac{\sum(x-\bar{x})^2}{n-1}}$

Sample standard deviation = $\sqrt{\frac{(21-23)^2+(25-23)^2+(23-23)^2+(22-23)^2+(24-23)^2+(21-23)^2+(25-23)^2+(21-23)^2+(23-23)^2+(26-23)^2+(21-23)^2+(24-23)^2+(22-23)^2+(24-23)^2+(23-23)^2+(21-23)^2+(21-23)^2+(26-23)^2+(23-23)^2+(24-23)^2}{20-1}}$

Sample standard deviation= s = $1.72$

Degree of freedom = n-1 = 20-1 -19

Critical value of t using the t-distribution table $t_{\frac{\alpha}{2}$ = 3.883

Formula of confidence interval : $\bar{x} \pm t_{\frac{\alpha}{2}} \times \frac{s}{\sqrt{n}}$

Substitute the values in the formula

Confidence interval : $23 \pm 1.73 \times \frac{1.72}{\sqrt{20}}$

Confidence interval : $23 -3.883 \times \frac{1.72}{\sqrt{20}}$ to $23 + 3.883 \times \frac{1.72}{\sqrt{20}}$

Confidence interval : $21.506$ to $24.493$

Hence Confidence interval : $21.506$ to $24.493$

3 0

3 years ago

Read 2 more answers

Answer!! Please. Will give brain.

damaskus [11]

Answer:

Step-by-step explanation:

Just trust me on this. It has got to be 58.

7 0

9 months ago

Plz give 8th and 9th question

Neko [114]

Answer:

for number 8 it is the multiplictivie inverse because you just do 8/9 x 2 so it would be correct and for number 9 it is not the multiplicative inverse because it is not reversing it also can i pls get brainliest

Step-by-step explanation:

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3 years ago

Which could be the measure of A.) 38 B.) 42 C.) 44 D.) 52

vichka [17]

Well you can check what type of angle it is! like depending on how it is slouched like a right angle is 90° for example.

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2 years ago