<span>The diagonals of a parallelogram bisect each other.
So we just equate the two equations BE and DE
2x^2 - x = x^2 + 6
2x^2 - x - x^2 - 6 = 0
x^2 - x - 6 = 0
This is quadratic eqn. So we obtain.
(x - 3) ( x + 2) = 0
Setting each to 0 and solving for x, we have that x = 3 and x = -2
So we have two possible values for BD.
But Since BE = DE then we can simply double each
If x = 3 BD = 2 (2(3)^2 - 3) = 2 ( 18 - 3) = 30 units
If x = - 2 BD = 2((-2)^2 -3 ) = 2 (8 - 3) = 10 units</span>
Answer:
Step-by-step explanation:
y=mx+b where m is the slope and b is the y intercept
m=(y2-y1)/(x2-x1), we have points (6,0) and (1,-1)
m=(-1-0)/(1-6)=1/5 so we have
y=x/5+b, using point (6,0) we can solve for b
0=6/5+b
b=-6/5
y=x/5-6/5 or more neatly
y=(x-6)/5
I tried to do my best to solve and show work. If you need an explanation just leave a comment :)
Umm subtract 7 from 5 2/7 and u will get 12/7
Therefore, the answer is 12/7
~~~~~~~~~2x- y - 1 = 0 ~~~~~~~~~~
