Answer:
0.9999
Step-by-step explanation:
Let X be the random variable that measures the time that a switch will survive.
If X has an exponential distribution with an average life β=44, then the probability that a switch will survive less than n years is given by
So, the probability that a switch fails in the first year is
Now we have 100 of these switches installed in different systems, and let Y be the random variable that measures the the probability that exactly k switches will fail in the first year.
Y can be modeled with a binomial distribution where the probability of “success” (failure of a switch) equals 0.0225 and
where
equals combinations of 100 taken k at a time.
The probability that at most 15 fail during the first year is
Answer:
11∗2+13∗4+15∗6+⋯+199∗100=?
=(1−12)+(13−14)+(15−16)+⋯+(199−1100)
=(1+13+15+17+⋯+199)−(12+14+16+⋯+1100)
=(1+13+15+17+⋯+199)−12(1+12+13+⋯+150)
=∑k=15012k−1−∑k=15012k
Continue further.
Answer:
-3/2 < x < 5......................
Answer:
So she can get the one 11in x 15in and then 10 3in x 5in
Step-by-step explanation:
The most she can spend is $11. and 11in x 14in photo would be to expensive to get 2 of them... sooo that one photo takes of 7
11-7= 4
A 3in x 5in photo cost just $.40 center (don't forget the decimal!)
So then you see how many times .40 will go into 4
4/.4 = 10
or .4z= 4; z= 10
Hope this helps ya! Brainliest answer by chance?
Hi there! Think of x as 2 and 6 and think of y as 8 and 12. 8-12/2-6=-4/-4. Now, -4/-4=1. Therefore, the answer is C. 1
