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vivado [14]
3 years ago
12

Use the diagram shown to answer the question. What is the value of sin Q?

Mathematics
1 answer:
scoundrel [369]3 years ago
4 0
The answer will going to be A
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A. 4(4) + 4 =20
16 + 4 =20
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An outlier always affects the mean.true or false
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This statement would be True
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Write 7.530 in word form.
Romashka [77]

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seven point five three zero

hope this helps you

3 0
3 years ago
Suppose a random variable, x, follows a Poisson distribution. Let μ = 2.5 every minute, find the P(X ≥ 125) over an hour. Round
Mashutka [201]

Answer:

P(X ≥ 125) = 0.9812

Step-by-step explanation:

To solve this question, we need to understand the Poisson distribution and the normal distribution.

Poisson distribution:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\lambda}*\lambda^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\lambda is the mean in the given interval, which is the same as the variance.

Normal distribution:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

The Poisson can be approximated to the normal, with \mu = \lambda, \sigma = \sqrt{\lambda}

Let μ = 2.5 every minute

This is the mean of the Poisson, so \lambda = 2.5n, in which n is the number of minutes.

P(X ≥ 125) over an hour

An hour has 60 minutes, so n = 60, \lambda = 2.5*60 = 150, \sigma = \sqrt{150} = 12.25

Using continuity correction, this is P(X \geq 125 - 0.5) = P(X \geq 124.5), which is 1 subtracted by the pvalue of Z when X = 124.5. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{124.5 - 150}{12.25}

Z = -2.08

Z = -2.08 has a pvalue of 0.0188

1 - 0.0188 = 0.9812

So

P(X ≥ 125) = 0.9812

8 0
3 years ago
Malaya is making a collage of her birthday party photos and she wants to add an 8 x 10 inch. photo. Since there is not enough sp
sergij07 [2.7K]

Answer:

The answer is C. 6.4 X 8 in

Step-by-step explanation:

If the scale factor from the original to the trimmed photo is 5:4

The statement above just means the scale of the old dimension is 5 while the scale of the new dimension is 4.

To get the new dimensions, multiply each of the old dimensions by 4/5

4/5 X 10 = 8

4/5 X 8 = 6.4

Therefore the new dimension is 6.4 X 8 in

3 0
4 years ago
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