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2 years ago

Perform the operation and, if possible, simplify 21/20 - 4/15

Mathematics

1 answer:

Kazeer [188]2 years ago

8 0

Answer:

47/60

Step-by-step explanation:

Find the LCM and multiply to get there.

LCM is 60

63/60-16/60

47/60

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weqwewe [10]

The answer would be $2.70

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3 years ago

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Use the diagram to determine which statement is true

hichkok12 [17]

A. Area of ABCD - Area of DGA = Area of DEFG
s^2 - 1/2bh = s^2
(5)^2 - 1/2(4)(3) = (3)^2
25 - 1/2(12) = 9
25 - 24 = 9
1 not equal to 9

B. Area of ABCD - Area of GHIA = Area of DGA
s^2 - s^2 = 1/2bh
(5)^2 - (4)^2 = 1/2(4)(3)
25 - 16 = 1/2(12)
9 not equal to 6

C. Area of ABCD + Area of DGA = Area of GHIA
s^2 + 1/2bh = s^2
(5)^2 + 1/2(4)(3) = (4)^2
25 + 1/2(12) = 16
25 + 6 = 16
31 not equal to 16

D. Area of DEFG + Area of GHIA = Area of ABCD
s^2 + s^2 = s^2
(3)^2 + (4)^2 = (5)^2
9 + 16 = 25
25 = 25

The answer is D.

5 0

3 years ago

Read 2 more answers

[WILL GIVE BRAINLIEST]

kirill115 [55]

Your answer is simple times 6 to 3 to get 18 then 15 by 8 to get 96 then add up everything to get 114

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3 years ago

If a restaurant bills totals $85, what amount should be left as a 15$ tips A. $97.75 B. $11.90 C.$12.25 D. $12.75

Nata [24]

If the total bill is $85, and you want to leave a 15% tip, then you can calculate it as follows:

85 * 15%

= 85 * 15/100

= 85 * 0.15

= 12.75

The amount that should be left as a tip is D. $12.75.

4 0

3 years ago

The amount of time, in minutes, that a woman must wait for a cab is uniformly distributed between zero and 12 minutes, inclusive

murzikaleks [220]

Answer:

$P(X\leq x) =\frac{x-a}{b-a}, a \leq x \leq b$

And using this formula we have this:

$P(X$

Then we can conclude that the probability that that a person waits fewer than 11 minutes is approximately 0.917

Step-by-step explanation:

Let X the random variable of interest that a woman must wait for a cab"the amount of time in minutes " and we know that the distribution for this random variable is given by:

$X \sim Unif (a=0, b =12)$

And we want to find the following probability:

$P(X$

And for this case we can use the cumulative distribution function given by:

$P(X\leq x) =\frac{x-a}{b-a}, a \leq x \leq b$

And using this formula we have this:

$P(X$

Then we can conclude that the probability that that a person waits fewer than 11 minutes is approximately 0.917

7 0

2 years ago