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DerKrebs [107]
2 years ago
15

Find the Area of the Shaded Portion: inches squared in sq

Mathematics
2 answers:
Zarrin [17]2 years ago
3 0
6×12 = 72
72 - (3x3) = 63

63 in ^2
vfiekz [6]2 years ago
3 0

answer:

63 inches squared

step-by-step explanation:

  • in order to find the area of just the shaded portion, we would have to subtract the not shaded portion from the whole rectangle
  • first, find the area of the whole rectangle

1 ft = 12 inches (conversion)

12 X 6 = 72 in^2 (area of the whole rectangle)

  • now, find the area of the not shaded portion

3 X 3 = 9 in^2 (area of the not shaded portion)

  • so, now that we have both areas, we just have to subtract them to find the area of the shaded portion

72 - 9 = 63

- - > 63 inches squared

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A The length of a rectangle is 4 m more
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Given :

  • The length of a rectangle is 4m more than the width.
  • The area of the rectangle is 45m²

⠀

To Find :

  • The length and width of the rectangle.

⠀

Solution :

We know that,

\qquad { \pmb{ \bf{Length \times Width = Area_{(rectangle)}}}}\:

So,

Let's assume the length of the rectangle as x and the width will be (x – 4).

⠀

Now, Substituting the given values in the formula :

\qquad \sf \: { \dashrightarrow x  \times  (x - 4) = 45 }

\qquad \sf \: { \dashrightarrow {x}^{2}  - 4x = 45 }

\qquad \sf \: { \dashrightarrow {x}^{2}  - 4x - 45 = 0 }

\qquad \sf \: { \dashrightarrow {x}^{2}    - 9x+ 5 x - 45 = 0 }

\qquad \sf \: { \dashrightarrow x(x - 9) + 5(x - 9) = 0 }

\qquad \sf \: { \dashrightarrow (x  - 9) (x  + 5) = 0 }

\qquad \sf \: { \dashrightarrow x = 9, \: \: x =  - 5}

⠀

Since, The length can't be negative, so the length will be 9 which is positive.

⠀

\qquad { \pmb{ \bf{ Length _{(rectangle)} = 9\:m}}}\:

\qquad { \pmb{ \bf{ Width _{(rectangle)} = 9 - 4=5\: m}}}\:

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