Draw a pizza with 10 slices and shade 3 slices
Answer: C
Step-by-step explanation:
If we know the value of the car decreases $500 for every 1,000 miles, and that the car is driven about 10,000 miles every year, that means that you need to take the total value of the car (23,000) and subtract it from the amount of money it is losing per year. Again, the car is driven about 10,000 miles per year, so that means that the car will most likely continue to be driven 10,000 miles per year. If you do the math, for one year, the value of the car will drop $5,000 ($500 x 10, because it is $500 per every 1,000 miles) So, for each year, you can just multiply the number of years by $5,000 to find out how much the vehicle has depreciated over time.
Hope this helped you and made sense! Feel free to ask me any questions you have!
Answer:
Log₆ (A⁵C² / D⁶) = –13
Step-by-step explanation:
From the question given above,
Log₆ A = 1
Log₆ C = 3
Log₆ D = 4
Log₆ (A⁵C² / D⁶) =?
Recall:
Log MN / U = Log M + Log N – Log U
Therefore,
Log₆ (A⁵C² / D⁶) = Log₆ A⁵ + Log₆ C² – Log₆ D⁶
Recall:
Log Mⁿ = nLog M
Thus,
Log₆ A⁵ + Log₆ C² – Log₆ D⁶
= 5Log₆ A + 2Log₆ C – 6Log₆ D
Log₆ A = 1
Log₆ C = 3
Log₆ D = 4
= 5(1) + 2(3) – 6(4)
= 5 + 6 – 24
= 11 – 24
= –13
Therefore,
Log₆ (A⁵C² / D⁶) = –13
Answer:
The answer to your question is: when x = 100 days, y = 34 m³
Step-by-step explanation:
Data
Volumen = 61 m³
Loses 0.27 m³ each day
Equation y + 0.27x = 61
when x = 100, y = ?
Process, just substitute x in the equation and solve it for y
y + 0.27(100) = 61
y + 27 = 61
y = 61 - 27
y = 34 m³
It means that after ten days, the swimming pool will only have 34 m³, because 27 m³ will have evaporated.
