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earnstyle [38]
2 years ago
10

What does b= in mathematics

Mathematics
1 answer:
ziro4ka [17]2 years ago
7 0

bisector. Base. In geometry, the base of a shape is the side (usually the bottom) that forms a right (90 degree) angle with the height of the object. Biannual.

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Solve for b. 4b-3b+7= 10
Morgarella [4.7K]

b = 3

Step-by-step explanation:

4b - 3b + 7 = 10

Add similar terms :

4b - 3b = b \\ b + 7 = 10

Collect like terms and simplify

b = 10 - 7 \\ b = 3

7 0
2 years ago
Read 2 more answers
Petra eats five and three fifths pies in a pie-eating contest. Paulie eats three and fourteen sixteenths pies in the contest. Ho
Alex777 [14]

Answer:

2 7/20

Step-by-step explanation:

So Lets put these into a fraction form

Petra: 5 3/5

Pauline: 3 4/16 -> Can be Simplified = 3 1/4

Take the number of pies Petra Ate and subtract it by the number of pies Pauline ate

Change the numbers to a common factor. (multiply 3/5 by 4 and 1/4 by 5 to have common denominators)

5 \frac{12}{20} - 3 \frac{5}{20}

Make These Into a Mixed Fraction

\frac{112}{20} -\frac{65}{20}

Subtract 112-65

\frac{47}{20}

Simplify (divide 47 into 20 how many times to get into a mixed fraction)

2 \frac{7}{20}

I think this is right. Hope This Helps

7 0
2 years ago
Read 2 more answers
A local artist working at the town fair makes caricatures and portraits. The caricatures cost $4 to make white
il63 [147K]

Answer:

The artist should make 15 caricatures and 30 portraits.

Step-by-step explanation:

First, we identify the variables for the problem. In this case, the variables will be:

C=number of caricatures

P= number of portraits.

Next, we can use the variables to make the inequalities that constrain the problem.

We know the artist can't spend more than $360 for supplies and we also know that it costs $4 to make a caricature and $10 to make a portrait, so:

4C+10P\le 360

We also know the artist has a limit of time of 20 hours, which is the same as 20*60=1200 minutes to paint. We know it takes her 20 minutes to make a caricature and 30 minutes to make a portrait, so:

20C+30P\le 1200

and we also know she must make a positive number of caricatures and a positive number of portraits so the other two constrains are:

C\ge 0

P\ge 0

So we can go ahead and graph them. (see attached picture)

Once we graphed the inequalities we can determine what the corners of the polygon created by the intersection of the shaded areas are, so we proceed and calculate them:

first point:

(0,0)

second point:

4(0)+10P=360

P=\frac{360}{10}

P=36

(0,36)

Third point:

20C+30(0)=1200

C=\frac{1200}{20}

C=60

(60,0)

Fourth point:

4C+10P = 360

20C+30P = 1200

We multiply the first equation by -5 so we get:

-20C-50P=-1800

20C+30P=1200

------------------------

-20P=-600

P=30

so:

20C+30(30)=1200

20C=1200-900

20C=300

C=15

(15,30)

Once we found the 4 points, we go ahead and evaluate them for the objective function. In this case, the objective function is the total amount of money she got from selling the pieces of art, so we get:

I=10C+20P

Point 1

I=10(0)+20(0)=0

Point 2

I=10(0)+20(36)=720

Point 3

I=10(60)+20(0)=600

Point 4

I=10(15)+20(30)=750

Next, we look for the greatest income which in this case will be 750 so that's why she must make 15 caricatures and 30 Portraits.

8 0
3 years ago
Please help me with this question, thank you and explain!!!
Novosadov [1.4K]

Total distance from w to z is -10 to 6 = 16

Add the ratios: 2 + 3 + 3 = 8

Divide distance by total ratio: 16/8 = 2

Multiply each ratio by 2 : 2x 2 = 4, 3 x 2 = 6, 3 x 2 = 6

WX is 4 units apart, add 4 to -10 to get x = -6

Answer: A. -6

5 0
2 years ago
What is the minimum number of x intercepts that a polynomial of degree 11 can? have?
stiks02 [169]

The degree of the polynomial will tell you the max amount of zeros you will have. 11 in this case.

However you can also have 9,7,5,3,1 (keep subtracting by 2)

So the answer is 1.
7 0
2 years ago
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