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saveliy_v [14]
3 years ago
12

A man walks in a straight path away from a streetlight at a rate of 4 feet per second. The man is 6 feet tall and the streetligh

t is 15 feet tall.
At what rate is the length of his shadow changing?
At what rate is the distance from the top of the streetlight to the tip of his shadow changing when the man is 12 feet from the streetlight?
Mathematics
1 answer:
Darina [25.2K]3 years ago
3 0

Answer:

a) 8/3 feet/second

b) 16/3 feet/second

Step-by-step explanation:

Let the length of the shadow be X

And initial distance from the streetlight be D

15/6 = (D + X)/X

15X = 6D + 6X

9X = 6D

X = ⅔D

dX/dD = ⅔

⅔ = dX/dt × dt/dD

dX/dt = ⅔ × 4 = 8/3

Distance from the tip is the hypotenuse 'H'

H² = 15² + (D + X)²

H² = 225 + (D + X)²

Differentiate both sides wrt time

2H × dH/dt = 2(D + X) × (dD/dt + dX/dt)

When D = 12, X = ⅔(12) = 8

D + X = 20

H² = 20² + 15²

H² = 625

H = 25

2(25) × dH/dt = 2(20) × (4 + 8/3)

dH/dt = 16/3

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5 0
4 years ago
Two fractions have denominators of x^2+ 6x + 9 and x^2. What is the Least Common Denominator?
Gala2k [10]

SOLUTION

Write out the denominator of the fraction, we have

\begin{gathered} x^2+6x+9 \\ \text{And } \\ x^2-9 \end{gathered}

We want to obtain the least common denominator.

To do this, we need to factorize each of the expression given

\begin{gathered} x^2+6x+9 \\ =x^2+3x+3x+9 \\ =x(x+3)+3(x+3) \\ =(x+3)(x+3) \end{gathered}

Then we factorise the other fraction using difference of two square

\begin{gathered} a^2-b^2=(a-b)(a+) \\ \text{Then} \\ x^2-9=x^2-3^2 \\ =(x-3)(x+3) \end{gathered}

The the factorise expression becomes

(x+3)(x+3)\text{ and (x-3)(x+3)}

To obtain the least common denominator, we select the common factor and the product of the other factor,

Hence

\begin{gathered} \text{common factor=(x+3)} \\ \text{The other factors are (x-3)(x+3)} \\ \text{Then } \\ \text{Least co}mmon\text{ denominator becomes } \\ (x+3)(x-3)(x+3) \end{gathered}

Thus

The Least Common Denominator is (x +3)(x+3)(x-3) (Last Option )

5 0
1 year ago
Combine these radicals. square root 27 and square root 3
sasho [114]

square root 27 is 3square root 3 so the answer is 2 square root three

5 0
3 years ago
Find the product of 6, m and 5
seropon [69]

The product is the result of an multiplication which means when have to multiply:

6 * 5 * m = 30m

The multiplication ends there since there is no given value for m.

Hope it helped,

Happy homework/ study/ exam!

3 0
3 years ago
Read 2 more answers
Let X be an exponential r.v. with mean 6 and Y be an uniform r.v. over [4, 10] independent of X. Find the variance of 2X+3Y.
Evgesh-ka [11]

Var[2X + 3Y] = 2² Var[X] + 2 Cov[X, Y] + 3² Var[Y]

but since X and Y are given to be independent, the covariance term vanishes and you're left with

Var[2X + 3Y] = 4 Var[X] + 9 Var[Y]

X follows an exponential distribution with parameter <em>λ</em> = 1/6, so its mean is 1/<em>λ</em> = 6 and its variance is 1/<em>λ</em>² = 36.

Y is uniformly distributed over [<em>a</em>, <em>b</em>] = [4, 10], so its mean is (<em>a</em> + <em>b</em>)/2 = 7 and its variance is (<em>b</em> - <em>a</em>)²/12 = 3.

So you have

Var[2X + 3Y] = 4 × 36 + 9 × 3 = 171

5 0
3 years ago
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