Area of a sector is x over 360 * pi r squares so in this case x would be 210 so it would be 210 over 360 and the pi r squared would be 24 pi and when we times that our answer is 14 pi

Answer:14 pi

8 0

3 years ago

Please help me find out what the question marks are

quester [9]

Question a

g(x) times $\sqrt{x-5}=\sqrt{x^2-5}$
divide both sides by √(x-5)
$g(x)=\frac{\sqrt{x^2-5}}{\sqrt{x-5}}$
$g(x)=\frac{(\sqrt{x-5})(\sqrt{x^2-5})}{x-5}$
$g(x)=\frac{\sqrt{x^3-5x^2-5x+25}}{x-5}$

question b
$g(x) \space\ times \space\ 1+\frac{1}{x}=x$
divide both sides by 1+1/x
$g(x)=\frac{x}{1+\frac{1}{x}}$
times by x/x
$g(x)=\frac{x^2}{x+1}$

question c
$\frac{1}{x} \space\ times \space\ f(x)=x$
times both sides by x
$f(x)=x^2$

question d
the (f*g)(x) collumn seems to have a domain of only x is greater than or equal to 0?
so maybe we squared the whole thing, ya
wait
ah, ya
basically
$|x|=(\sqrt{x})^2=(\sqrt{x})(\sqrt{x})$
so f(x)=√x

a. $g(x)=\frac{\sqrt{x^3-5x^2-5x+25}}{x-5}$
b. $g(x)=\frac{x^2}{x+1}$
c. $f(x)=x^2$
d. $f(x)=\sqrt{x}$

3 0

4 years ago

Read 2 more answers

(Look at the picture, please.)

AysviL [449]

Answer:

the answer is D : 1/2 :))))))

5 0

3 years ago

Read 2 more answers

Please help me it's urgent ​

Please help me it's urgent