The answer to the question is letter d, 6 1/4 inches.
The numbers in this problem are ordered pairs, which are points on a graph.
These are (10, 20), (-10, 20), (-10, -10), and (10, -10).
To find the area and perimeter of this shape, you must first find the distance between each point.
Distance between (10, 20) and (-10, 20):
Since the y-value remains the same here, we just have to find the difference in x-values.
This means 10 - (-10)
A negative being subtracted is the same as a positive being added.
That means 10 - (-10) is the same as 10 + 10.
10 + 10 = 20, so the distance between (10, 20) and (-10, 20) is 20 units.
Distance between (-10, 20) and (-10, -10):
The x-values are the same here so just find the difference between the y-values.
20 - (-10) = 20 + 10 = 30
The distance between the (-10, 20) and (-10, -10) is 30 units.
Distance between (-10, -10) and (10, -10):
The y-values are the same so just find the difference between the x-values.
10 - (-10) = 10 + 10 = 20
The distance between (-10, -10) and (10, -10) is 20 units.
Distance between (10, -10) and (10, 20):
The x-values are the same so find the difference between the y-values.
20 - (-10) = 20 + 10 = 30
The distance between (10, -10) and (10, 20) is 30 units.
So now we know the side lengths of the room are 20 units, 30 units, 20 units, and 30 units.
To find the perimeter, add all the side lengths together.
20 + 30 + 20 + 30 = 100
The perimeter of the room is 100 units.
To find the area, multiply the length by the width.
The length is 20 units and the width is 30 units.
20 • 30 = 600
The area of the room is 600 units.
Final answers:
Perimeter = 100
Area = 600
Hope this helps!
Answer:
y = 2x
Step-by-step explanation:
Given y is directly proportional to x then the equation relating them is
y = kx ← k is the constant of proportion
To find k use the condition when x = 4, y = 8, that is
8 = 4k ( divide both sides by 4 )
2 = k, thus
y = 2x ← equation of proportion
The distance between the anchor points of the two guy wires holding radio antenna is 181 feet (to the nearest foot)
<h3>How to determine the distance between the two anchor points of the guy wire</h3>
The problem will be solved using SOH CAH TOA
let the distance between the 150 ft long guy wire and the radio antenna be x
let the distance between the 180 ft long guy wire and the radio antenna be y
cos 65° = x / 150
x = cos 65° * 150
x = 63.39 ft
The height of the antenna
sin 65° = height of antenna / 150
height of antenna = sin 65 * 150
height of antenna = 135.95
using Pythagoras theorem
(length of guy wire)² = (height of the antenna)² + (anchor distance)²
(anchor distance)² = 180² - 135.95²
anchor distance = √(180² - 135.95²)
anchor distance = 117.97
The anchor points distance apart
= 63.39 + 117.97
= 181 (to the nearest foot)
Learn more on Pythagoras theorem here:
brainly.com/question/29241066
#SPJ1
