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Goryan [66]
3 years ago
11

Solve for u. -6=-2u +4(u-5)

Mathematics
2 answers:
g100num [7]3 years ago
7 0

Answer:

7  = u

Step-by-step explanation:

sergij07 [2.7K]3 years ago
5 0

Answer: u=7

Step-by-step explanation:

-6= -2u+4(u-5)

-6= -2u+4u-20

-6= 2u-20

14= 2u

7=u

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Solve for x<br> pls show work<br> 1/2*(x - -6)= -1
Pavlova-9 [17]

Answer: x = -4

Step-by-step explanation:

1/2 * (x - (-6)) = 1

distribute

1/2x + 3 = 1

isolate the variable

1/2x = -2

x = - 4

5 0
3 years ago
What is the probability of flipping two coins and both landing on heads
prisoha [69]

Answer:

The probability of getting heads on the toss of a coin is 0.5. If we consider all possible outcomes of the toss of two coins as shown, there is only one outcome of the four in which both coins have come up heads, so the probability of getting heads on both coins is 0.25. The second useful rule is the Sum Rule.

3 0
3 years ago
Read 2 more answers
John's bank notified him that he had a negative checking account balance of -$125.70. If John makes two deposits of $89.32 each,
NeX [460]
The answer is 52.94 because since it said he made to deposits of 89.32 you and that together and your result is 173.64 and then you subtract that from -125.70 and you get 52.94
5 0
3 years ago
Find The surface area of a cone with a radius of 7 and slant hight of 9
liubo4ka [24]

Answer:14

Step-by-step explanation:

4 0
3 years ago
For a fair coin, suppose you toss the coin 100 times.
Natasha_Volkova [10]

Using the normal distribution, it is found that there is a 0.0005 = 0.05% probability of getting more than 66 heads.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean \mu and standard deviation \sigma is given by:

Z = \frac{X - \mu}{\sigma}

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
  • The binomial distribution is the probability of x successes on n trials, with p probability of a success on each trial. It can be approximated to the normal distribution with \mu = np, \sigma = \sqrt{np(1-p)}.

For the binomial distribution, the parameters are given as follows:

n = 100, p = 0.5.

Hence the mean and the standard deviation of the approximation are given as follows:

  • \mu = np = 100(0.5) = 50.
  • \sigma = \sqrt{np(1-p)} = \sqrt{100(0.5)(0.5)} = 5

Using continuity correction, the probability of getting more than 66 heads is P(X > 66 + 0.5) = P(X > 66.5), which is <u>one subtracted by the p-value of Z when X = 66.5</u>.

Z = \frac{X - \mu}{\sigma}

Z = \frac{66.5 - 50}{5}

Z = 3.3

Z = 3.3 has a p-value of 0.9995.

1 - 0.9995 = 0.0005.

0.0005 = 0.05%

More can be learned about the normal distribution at brainly.com/question/4079902

#SPJ1

6 0
2 years ago
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