Let s = the speed of the slower train in km/hrs+10 = the speed of the faster train in km/hrLet t = time in hrs for the slower train to go 160 kmt-5 = time in hrs for faster train to go 160 km---------------Slower train:(1)
160=s.t
Faster train:(2) 160=(s+10) .(t-.5)From (1)(1) t=160/s
use the relations given in following screenshot and then use quadratic equation.
Answer:
-3
Step-by-step explanation:
You subtract y values and divide by difference in x values
2-5=-3
4-3=1
-3/1=-3
Answer:
ans : general term = (2n +8)/(4^n) * (-1)^n
It should be for 5 hours if $30 is what they started with
X=7
Hope this helps and have a wonderful day!