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shusha [124]
3 years ago
14

HELPPPPP MEEE PLEASE

Mathematics
1 answer:
Brut [27]3 years ago
4 0
The answer is C I think
You might be interested in
Volume of cylinder, write the term in pie
gladu [14]

Answer:

vol of cylinder = per. of base x height + 2 (area of base)

area of base = pi x r^2

4pi = pi r^2

4=r^2

r=2

per of base = 2 x pi x r

2xpix2=4pi (same as area cause 2x2 and 2^2 is the same thing)

4pi + 2(4pi)

4pi + 8pi

<u>12pi  = volume</u>

<u />

<u>hope that answers your question</u>

<u>Don't hesitate to comment if you are confused about something</u>

Step-by-step explanation:

3 0
3 years ago
What’s the answer???(ONLY ANSWER IF YOU KNOW PLEASE)
arsen [322]

x-4 needs to be greater or equal to zero so

[4, ∞) is the answer

3 0
4 years ago
Find the distance from the point to the line. (-1,-2,1);x=4+4t, y=3+t, z=6-t .The distance is ____ Typn exact answer, using radi
lawyer [7]

Answer:

The distance is<u>  4.726 </u>

Step-by-step explanation:

we need to find the distance from the point to the line

Given:- point (-1,-2,1) and line ; x=4+4t, y=3+t, z=6-t .

used formula d=\frac{|a\times b|}{|a|}

Let point P be (-1,-2,1)

using value t=0 and t=1

The point Q (4 , 3, 6) and R ( 8, 4, 5)

Let a be the vector from Q to R :   a = < 8 - 4, 4 - 3, 5 - 6 > = < 4, 1, -1 >

Let b be the vector from Q to P:    b = < -1 - 4, -2 - 3, 1 - 6> = < -5, -5, -5 >

The cross product of a and b is:

a \times b= \begin{vmatrix} i & j & k\\ 4 &1&-1\\-5 &-5&-5\\ \end{vmatrix}

= -6i+15j-15k

The distance is : d=\frac{\sqrt{(-6)^{2}+(15)^{2}+(-15)^{2}}}{\sqrt{(4)^{2}+(1)^{2}+(-1)^{2}}}

=\frac{\sqrt{36+225+225}}{\sqrt{16+1+1}}

=\frac{\sqrt{36+225+225}}{\sqrt{16+1+1}}

d=\frac{\sqrt{486}}{\sqrt{18}}

≈4.726

Therefore, the distance is<u>  4.726 </u>

3 0
3 years ago
PLEASE HELP!
Gekata [30.6K]
First: 13 x 8 = 104
Second: 8/2 = 4 
Third: 104 + 4 = 108 
Your answer is 108


5 0
3 years ago
From the sum of 3a^2-ab-2b^2 and 2a^2+5ab-3b^2 subtract a^2-3ab-4b^2
Luden [163]

4a^2+7ab-b^2

Step-by-step explanation:

Add the first two equations together:

 3a^2-ab-2b^2

+ 2a^2+5ab-3b^2

---------------------------

5a^2+4ab-5b^2

Subtract that answer from the remaining trinomial:

5a^2+4ab-5b^2

- a^2-3ab-4b^2

--------------------------

4a^2+7ab-b^2

3 0
3 years ago
Read 2 more answers
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