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Amiraneli [1.4K]
3 years ago
14

In which situation would hydrogen bonding be present?

Mathematics
1 answer:
Law Incorporation [45]3 years ago
4 0

Answer:

D

Step-by-step explanation:

lol this is a weird math question

jk

Hydrogen bonds occur only when hydrogen is covalently bonded to one of three elements: fluorine, oxygen, or nitrogen. Anything else isn't considered a hydrogen bond.

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An Experienced ice skater spins on the ice, creating a perfect circle with a diameter of 4 feet. What is the circle's radius?
Fed [463]

Answer:

2

Step-by-step explanation:

the radius is half the diameter from the middle!

8 0
2 years ago
If the length and width of rectangle A are each k times the length and width of rectangle B, which statement is true?
Svetach [21]

Answer:

B

Step-by-step explanation:

the area of triangle A is k times the area of triangle b

8 0
3 years ago
100 POINTS HEY YALL IS THIS LINE OF BEST FIT A LINE OF BEST FIT LOL
telo118 [61]

Answer:

try and angle it more upwards so that it goes more through the second dot from the top and those 2 dots towards the bottom of the graph above the line.

Step-by-step explanation:

8 0
2 years ago
4x^2+4x+1=9 solutions
Artyom0805 [142]

Answer:

4(x-2)(x+1)=0

Step-by-step explanation:

5 0
3 years ago
In a quality control test of parts manufactured at Dabco Corporation, an engineer sampled parts produced on the first, second, a
sammy [17]

Answer:

p value = 0.0174

Conclusion : we reject the null hypothesis

Step-by-step explanation:

Thinking step:

We need to perform a test to determine if the proportion of the good parts is the same for all three shifts at a significance level of \alpha = 0.05

Assumption : all the population for each or the three shifts is not equal.

Calculation:

Let p₁ be the sample of the first shift

     p₂ be the sample of the second shift

     p₃ be the sample of the third shift

According to the null hypothesis

H₀ = p₁ = p₂ = p₃

In other words, all the population sample proportions are equal.

Alternatively, we can assume that the three shift are not equal p₁ ≠ p₂ ≠ p₃

Tabulating and performing the \chi² test gives 8.10

degrees of freedom:

df = k - 1

   = 3 - 1 = 2

Thus the degree of freedom is 2

Solving using the MINITAB software gives: p = 0.174

The solution shows that the p value < level of significance, then p-value lies in the range 0.0174≤\alpha≤0.05

Therefore, we reject the null hypothesis based on the fact that the three shifts are not equal.

5 0
2 years ago
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