In which situation would hydrogen bonding be present?
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I'm assuming you're looking to find the expanded form of the number?
This number is in scientific notation. The easiest way to convert it to a normal number is to move the decimal place 14 to the right. I've attached a picture showing how to do this. You should get 630,000,000,000,000
There's a faster way to do this - notice that you need to move the decimal 14 to the right, and there's one number already after the decimal place. Therefore, 13 places will be filled with zeros. So, just write out 63 and add 13 zeros.
For more general help on scientific notation, check out these videos: https://www.khanacademy.org/math/pre-algebra/pre-algebra-exponents-radicals/pre-algebra-scientific-notation/v/scientific-notation-old
Hope that helps! Feel free to message me or leave a comment if I can clarify anything :)
345= 3 hundreds, 4 tens, and 5 ones
391= 3 hundreds, 9 tens, and 1 one
You can use the model I attached to help u see it better.
Hope this helps!
391= 3 hundreds, 9 tens, and 1 one
You can use the model I attached to help u see it better.
Hope this helps!