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vlada-n [284]
3 years ago
6

Can anyone do this need help:)

Mathematics
1 answer:
Alexus [3.1K]3 years ago
8 0

Answer: step 4 because you have to divide it not subtract it

Step-by-step explanation:

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Solve the following inequality for x. -5x<-15x+40
melisa1 [442]

Answer:

x is less than 4

or

x is greater than 4

Step-by-step explanation:

-5x < -15x + 40 -5x < -15x + 40

+15x +15x -40 -40

10x < 40 -40 - 5x < -15x

÷10 ÷10 +5x +5x

× < 4 -40 < -10x

÷10 ÷10

4 < ×

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3 years ago
125 pounds decreased by 4% what is the new amount
Anvisha [2.4K]

You want 125 pounds minus 4% of it, so you want 96% just multiply it

125 . 96% = 125 . 96/100 = 120

3 0
3 years ago
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Explain how to use the vertex and the value of “A” to determine the range of an absolute value function. PLEASE HELP!!
Thepotemich [5.8K]

Answer:

First, a absolute value function is something like:

y = f(x) = IxI

remember how this work:

if x ≥ 0, IxI = x

if x ≤ 0, IxI = -x

Notice that I0I = 0.

And the range of this function is all the possible values of y.

For example for the parent function IxI, the range will be all the positive reals and the zero.

First, if A is the value of the vertex of the absolute function, then we know that A is the maximum or the minimum value of the function.

Now, if the arms of the graph open up, then we know that A is the minimum of the function, and the range will be:

y ≥ A

Or all the real values equal to or larger than A.

if the arms of the graph open downwards, then A is the maximum of the function, and we have that the range is:

y ≤ A

Or "All the real values equal to or smaller than A"

5 0
3 years ago
If f(x)=3<img src="https://tex.z-dn.net/?f=x%5E%7B2%7D" id="TexFormula1" title="x^{2}" alt="x^{2}" align="absmiddle" class="late
Anvisha [2.4K]

Answer:

\sf f(-3) = 23

<u>given:</u>

\sf f(x) = 3x^2 -4

to find the output, replace x with the given integer.

solve:

\sf f(-3) = 3(-3)^2 -4

\sf f(-3) = 3(9) -4

\sf f(-3) = 27 -4

\sf f(-3) = 23

5 0
2 years ago
Help me with this homework!!!!!!!!!!
Nikolay [14]
Help you with what homework???
6 0
3 years ago
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