Check the picture below.
![\textit{area of a regular polygon}\\\\ A=\cfrac{1}{2}asn ~~ \begin{cases} a=apothem\\ n=\stackrel{side's}{number}\\ s=\stackrel{side's}{length}\\[-0.5em] \hrulefill\\ a=7\\ s=8.1\\ n=6 \end{cases}\implies \stackrel{\textit{area of the hexagonal base}}{A=\cfrac{1}{2}(7)(8.1)(6)} \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=%5Ctextit%7Barea%20of%20a%20regular%20polygon%7D%5C%5C%5C%5C%20A%3D%5Ccfrac%7B1%7D%7B2%7Dasn%20~~%20%5Cbegin%7Bcases%7D%20a%3Dapothem%5C%5C%20n%3D%5Cstackrel%7Bside%27s%7D%7Bnumber%7D%5C%5C%20s%3D%5Cstackrel%7Bside%27s%7D%7Blength%7D%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20a%3D7%5C%5C%20s%3D8.1%5C%5C%20n%3D6%20%5Cend%7Bcases%7D%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Barea%20of%20the%20hexagonal%20base%7D%7D%7BA%3D%5Ccfrac%7B1%7D%7B2%7D%287%29%288.1%29%286%29%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill)
![\textit{volume of a prism}\\\\ V=Bh ~~ \begin{cases} B=\stackrel{base's}{area}\\ h=height\\[-0.5em] \hrulefill\\ B=\frac{1}{2}(7)(8.1)(6)\\ V=3572.1 \end{cases}\implies 3572.1=\cfrac{1}{2}(7)(8.1)(6)h \\\\\\ 3572.1=170.1h\implies \cfrac{3572.1}{170.1}=h\implies \boxed{21=h}](https://tex.z-dn.net/?f=%5Ctextit%7Bvolume%20of%20a%20prism%7D%5C%5C%5C%5C%20V%3DBh%20~~%20%5Cbegin%7Bcases%7D%20B%3D%5Cstackrel%7Bbase%27s%7D%7Barea%7D%5C%5C%20h%3Dheight%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20B%3D%5Cfrac%7B1%7D%7B2%7D%287%29%288.1%29%286%29%5C%5C%20V%3D3572.1%20%5Cend%7Bcases%7D%5Cimplies%203572.1%3D%5Ccfrac%7B1%7D%7B2%7D%287%29%288.1%29%286%29h%20%5C%5C%5C%5C%5C%5C%203572.1%3D170.1h%5Cimplies%20%5Ccfrac%7B3572.1%7D%7B170.1%7D%3Dh%5Cimplies%20%5Cboxed%7B21%3Dh%7D)
well, the length of the tunnel is "h", now two 8 meters cars, that's 8+8=16 meters plus a 3 meter connector between them, that's 16 + 3 = 19 meters, can those two cars connected like so fit inside the tunnel? sure thing, "h" can fit 19 meters just fine.
Answer:
is there more to the question? this does not make seince
Step-by-step explanation:
Answer:
x = - 5, x = 7
Step-by-step explanation:
Given
x² - 2x - 35 = 0
Consider the factors of the constant term (- 35) which sum to give the coefficient of the x- term (- 2)
The factors are - 7 and + 5, since
- 7 × 5 = - 35 and - 7 + 5 = - 2, thus
(x - 7)(x + 5) = 0
Equate each factor to zero and solve for x
x + 5 = 0 ⇒ x = - 5
x - 7 = 0 ⇒ x = 7
Answer:
k ≥ -18
Step-by-step explanation:
-8 ≥ 2/5(k-2)
-8 ≥ 2/5k - 4/5
(-8 ≥ 2/5k - 4/5) 5
-40 ≥ 2k - 4
+4 +4
-36 ≥ 2k
-36 divided by 2
2 divided by 2
-18 ≥ k
flip the greater than or equal to sign to the k.
k ≥ -18
Many statements can be true about those parabolas, so you need to include the list of choices.
This is the list of answer choices that I found for this same question:
<span>A. The second parabola opens downward.
B. The second parabola opens upward.
C. The points of intersection are on the x-axis.
D. The points of intersection are of equal distance from the y-axis.
While A, B or C may be or may not be true, D has to be true.
D. has to be true because the symetry axis of both parabolas is x = 0, so the intersection points will be necesarily to the same distance of the x-axis and the y-axis.
Answer: </span>
<span>The points of intersection are of equal distance from the y-axis.
</span>
