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Alex Ar [27]
3 years ago
12

A set of data has a sample mean of 65.4 and a standard deviation of 1.2. If the sample size is 45. what is the 99% confidence in

terval of this data?
OA
64.94 and 65.86
ОВ.
65.05 and 65.75
Ос.
65.10 and 65.70
OD
65.33 and 65.47
Mathematics
1 answer:
bagirrra123 [75]3 years ago
6 0
67.55 is the correct answe bec I add
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Is this correct? Yes or nah
lara31 [8.8K]
There are 20 squares total you shaded 5
\frac{5}{20} = \frac{1}{4} = 25\%
5 0
3 years ago
Determine the number of terms, n, given the geometric series 1 3 9 27 ... and sn=3280.
lina2011 [118]

The number of terms, 'n' is 8

<h3 /><h3>How to determine the number of terms</h3>

Let's determine the common ratio;

common ratio, r = 3/1 = 3

The formula for sum of geometric series with 'r' greater than 1 is given as;  Sn = a( r^n - 1) / (r - 1)

n is unknown

Sn = 3280

Substitute the value

3280 = 1 ( 3^n - 1) / 3- 1

3280 = 3^n -1 /2

Cross multiply

3280 × 2 = 3^n - 1

6560 + 1 = 3^n

6561 = 3^n

This could be represented as;

3^8 = 3^n

like coefficient cancels out

n = 8

Thus, the number of terms, 'n' is 8

Learn more about geometric series here:

brainly.com/question/24643676

#SPJ1

5 0
2 years ago
which one of the following proportions is true for the segments shown in the figure if lines a B and C are parallel to each othe
ycow [4]
I believe it is A because line segment AC is equal to line segment BD, and AE and BF are also the same
5 0
4 years ago
An engineer is planning a new water pipe installation. The circular pipe has a diameter of d=20\text{ cm}d=20 cmd, equals, 20, s
aivan3 [116]

Answer: The answer is 314.28 cm² (approx.).


Step-by-step explanation:  Given that an engineer is going to install a new water pipe. The diameter of this circular pipe is, d = 20 cm.

We need to find the area 'A' of the circular cross-section of the pipe.

Given, diameter of the circular section is

\textup{d}=20~\textup{cm}.

So, the radius of the circular cross-section will be

\textup{r}=\dfrac{\textup{d}}{2}=\dfrac{20}{2}=10~\textup{cm}.

Therefore, cross-sectional area of the pipe is

\textup{A}=\pi \textup{r}^2=\dfrac{22}{7}(10)^2=\dfrac{2200}{7}=314\dfrac{2}{7}=314.28~.~.~.~\textup{cm}^2.

Thus, the answer is 314.28 cm² (approx.).

4 0
4 years ago
Please help me I have
monitta

Answer: a or D

y e s maybe wrong

8 0
3 years ago
Read 2 more answers
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