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lord [1]
3 years ago
10

At what point does she lose contact with the snowball and fly off at a tangent? That is

Mathematics
1 answer:
postnew [5]3 years ago
4 0

Answer:

α ≥ 48.2°

Step-by-step explanation:

The complete question is given as follows:

" A skier starts at the top of a very large frictionless snowball, with a very small initial speed, and skis straight  down the side. At what point does she lose contact with the snowball and fly off at a tangent? That is, at the  instant she loses contact with the snowball, what angle α does a radial line from the center of the snowball to  the skier make with the vertical?"

- The figure is also attached.

Solution:

- The skier has a mass (m) and the snowball’s radius (r).

- Choose the center of the snowball to be the zero of gravitational  potential. - We can look at the velocity (v) as a function of the angle (α) and find the specific α at which the skier lifts off and  departs from the snowball.

- If we ignore snow-­ski friction along with air resistance, then the one work producing force in this problem, gravity,  is conservative. Therefore the skier’s total mechanical energy at any angle α is the same as her total mechanical  energy at the top of the snowball.

- Hence, From conservation of energy we have:

                       KE (α) + PE(α) = KE(α = 0) + PE(α = 0)

                       0.2*m*v(α)^2 + m*g*r*cos(α) = 0.5*m*[ v(α = 0)]^2 + m*g*r

                       0.2*m*v(α)^2 + m*g*r*cos(α) ≈ m*g*r

                        m*v(α)^2 / r = 2*m*g( 1 - cos(α) )

- The centripetal force (due to gravity) will be mgcosα, so the skier will remain on the snowball as long as gravity  can hold her to that path, i.e. as long as:

                         m*g*cos(α) ≥ 2*m*g( 1 - cos(α) )

- Any radial gravitational force beyond what is necessary for the circular motion will be balanced by the normal  force—or else the skier will sink into the snowball.

- The expression for α_lift becomes:

                            3*cos(α) ≥ 2

                            α ≥ arc cos ( 2/3) ≥ 48.2°

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if you divide a positive number by 12, the answer would be less than the original number? always, sometimes, or never​
elena55 [62]

Answer:

Always

Step-by-step explanation:

The rules for positive numbers is that addition and multiplication makes numbers larger. Subtraction and division makes numbers smaller.

Since 12 is a positive number, the result of dividing a positive number by 12 will make it smaller.

8 0
3 years ago
Suppose that 10 years ago you bought a home for $160,000, paying 10% as a down payment, and financing the rest at 9% interest fo
Goshia [24]

Answer:

Current monthly payment on their existing mortgage would be $1158.66

Step-by-step explanation:

Total cash value = $160,000

Down payment = 10% of 160,000

Down Payment = $16,000

Balance amount = 160,000 - 16,000 = $144,000

Monthly payment formula:

P=\dfrac{r(PV)}{1-(1+r)^{-n}}

where,

PV is present value of home, PV=$144,000

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Monthly payment would be same for 30 years.

Thus, Current monthly payment on their existing mortgage would be $1158.66

5 0
3 years ago
Is 3/2 an allowable probability? Explain.
nadezda [96]
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7 0
3 years ago
brooke found the equation of the line passing through the points (-7,25) and (-4,13) in slope-intercept form as follows​
Goryan [66]

Answer:

The equation of the line passing through the points (-7,25) and (-4,13) in slope-intercept form is \mathbf{y=-4x-3}

Step-by-step explanation:

Equation of line passing through the points (-7,25) and (-4,13) in slope-intercept form.

The general equation of slope-intercept form is: y=mx+b

First we need to find slope

The formula used for finding slope is: Slope=\frac{y_2-y_1}{x_2-x_1}

We are given: x_1=-7, y_1=25, x_2=-4, y_2=13

Putting values in formula and finding slope

Slope=\frac{y_2-y_1}{x_2-x_1}\\Slope=\frac{13-25}{-4-(-7)}\\Slope=\frac{13-25}{-4+7}\\Slope=\frac{-12}{3}\\Slope=-4

So, slope m= -4

Now finding y-intercept

Using slope m=-4 and point (-7,25) we can find y-intercept

y=mx+b\\25=-4(-7)+b\\25=28+b\\b=25-28\\b=-3

So, y-intercept b =-3

Now, the equation of required line having slope m=-4 and  y-intercept b=-3 is:

y=mx+b\\y=-4x-3

So, the equation of the line passing through the points (-7,25) and (-4,13) in slope-intercept form is \mathbf{y=-4x-3}

3 0
3 years ago
Me podrían ayudar y explicarme el proceso please
kakasveta [241]

Answer: Encontrarás las respuestas debajo de cada explicación. Espero que consideres darme brainliest y 5 estrellas, y más importante, que hayas entendido.

Step-by-step explanation:

Esto es la regla de 3. Conoces 3 valores y necesitas encontrar un 4to valor.

Ya sabemos que 1 caja pesa 20kg,

1 - 20kg

ahora queremos saber cuantas cajas (x) equivalen a 7653kg

x - 7653kg

Hacemos un pequeño cuadro poniendo en un lado los numeros de cajas y del otro el peso.

Pongamos la cantidad de cajas en la izquierda y el peso en la derecha

\frac{1}{x} =\frac{20kg}{7653kg}

Procedemos a multiplicar en cruz. Solo podemos multiplicar si tenemos ambos valores. En este caso, los valores en cruz que tenemos son 1 y 7653kg porque en la otra cruz (20 y x) tenemos nuestra incognita. Y, por ultimo, dividimos entre el numero cuya cruz es con la incognita (20kg)

Esto nos deja la expresión así;

x=\frac{1*7653kg}{20kg}

x=382.65

Como una caja no puede ser un numero decimal, redondeamos.

x=383

Por lo tanto, se necesitan aproximadamente 383 cajas para que su peso equivalga a 7653 kg.

-------------------------------------------------------------------------------------------------------

La otra pregunta dice: Si una caja pesa 20kg, (1 - 20kg), ¿Cuántas cajas se necesitan para equivaler 9500kg? (x - 9500kg)

Hacemos lo mismo que arriba, ponemos la cantidad de cajas de un lado, y el peso de otro lado.

\frac{1}{x}=\frac{20kg}{9500kg}

Multiplicamos aquellos valores en cruz que conozcamos y dividimos por el valor cuya cruz sea con x.

x=\frac{1*9500kg}{20kg}

x=475

Esta es la cantidad de cajas que se necesitan para que su pesa equivalga a 9500kg.

--------------------------------------------------------------------------------------------------------

Por último, la pregunta dice, ¿Cuántos kilogramos hay en 873 cajas?

Ya sabemos que una caja pesa 20kg ( 1 - 20kg ) y ahora buscamos cuantos kg hay en 873 cajas; es decir, (873 - x)

Nos quedaría así;

\frac{1}{873}=\frac{20kg}{x}

Ahora, nuestra cruz es 873 y 20kg, y el divisor es 1.

x=\frac{873*20kg}{1}

x=17460kg

Este sería el peso de 873 cajas.

5 0
3 years ago
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