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2 years ago

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The height(in ft) of a golf ball hit in the air is given by the equation h(t) = -16t^2 + 128t, where t represents the time in se

conds after it was hit.
Part A) Find the maximum height reached by the golfball.

Part B) For how many seconds was the golfball in the air? Or how long did it take for the golfball to reach the ground?

2 answers:

Rus_ich [418]2 years ago

7 0

The correct answer is 100 for both

UkoKoshka [18]2 years ago

5 0

Answer:

100 for both

Step-by-step explanation:

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How would you do this???

Kobotan [32]

Answer:

8.3 L/s

Step-by-step explanation:

To find the answer you need to find the slope also known as the rate of change. When you find slope it is always change in y over change in x.

$\frac{399-150}{40-10}$

Then simplify

$\frac{249}{30}$

Then divide to get your slope/average rate of change

$\frac{249}{30}$ = 8.3

6 0

3 years ago

Explain your answer !! <br> Have a nice day <br><br> Will give braisnlt

Stels [109]

The answer is B because in total you there are 15 bicycles and tricycles so b +t =15
Bicycles have 2 wheels and tricycles have 3 wheels so 2b + 3t = 45

6 0

3 years ago

Which of the following data could be graphed using a dot plot?Select all that apply.

ExtremeBDS [4]

Answer:

what are the options?

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Determine which of the sets of vectors is linearly independent. A: The set where p1(t) = 1, p2(t) = t2, p3(t) = 3 + 3t B: The se

defon

Answer:

The set of vectors A and C are linearly independent.

Step-by-step explanation:

A set of vector is linearly independent if and only if the linear combination of these vector can only be equalised to zero only if all coefficients are zeroes. Let is evaluate each set algraically:

$p_{1}(t) = 1$ , $p_{2}(t)= t^{2}$ and $p_{3}(t) = 3 + 3\cdot t$ :

$\alpha_{1}\cdot p_{1}(t) + \alpha_{2}\cdot p_{2}(t) + \alpha_{3}\cdot p_{3}(t) = 0$

$\alpha_{1}\cdot 1 + \alpha_{2}\cdot t^{2} + \alpha_{3}\cdot (3 +3\cdot t) = 0$

$(\alpha_{1}+3\cdot \alpha_{3})\cdot 1 + \alpha_{2}\cdot t^{2} + \alpha_{3}\cdot t = 0$

The following system of linear equations is obtained:

$\alpha_{1} + 3\cdot \alpha_{3} = 0$

$\alpha_{2} = 0$

$\alpha_{3} = 0$

Whose solution is $\alpha_{1} = \alpha_{2} = \alpha_{3} = 0$ , which means that the set of vectors is linearly independent.

$p_{1}(t) = t$ , $p_{2}(t) = t^{2}$ and $p_{3}(t) = 2\cdot t + 3\cdot t^{2}$

$\alpha_{1}\cdot p_{1}(t) + \alpha_{2}\cdot p_{2}(t) + \alpha_{3}\cdot p_{3}(t) = 0$

$\alpha_{1}\cdot t + \alpha_{2}\cdot t^{2} + \alpha_{3}\cdot (2\cdot t + 3\cdot t^{2})=0$

$(\alpha_{1}+2\cdot \alpha_{3})\cdot t + (\alpha_{2}+3\cdot \alpha_{3})\cdot t^{2} = 0$

The following system of linear equations is obtained:

$\alpha_{1}+2\cdot \alpha_{3} = 0$

$\alpha_{2}+3\cdot \alpha_{3} = 0$

Since the number of variables is greater than the number of equations, let suppose that $\alpha_{3} = k$ , where $k\in\mathbb{R}$ . Then, the following relationships are consequently found:

$\alpha_{1} = -2\cdot \alpha_{3}$

$\alpha_{1} = -2\cdot k$

$\alpha_{2}= -2\cdot \alpha_{3}$

$\alpha_{2} = -3\cdot k$

It is evident that $\alpha_{1}$ and $\alpha_{2}$ are multiples of $\alpha_{3}$ , which means that the set of vector are linearly dependent.

$p_{1}(t) = 1$ , $p_{2}(t)=t^{2}$ and $p_{3}(t) = 3+3\cdot t +t^{2}$

$\alpha_{1}\cdot p_{1}(t) + \alpha_{2}\cdot p_{2}(t) + \alpha_{3}\cdot p_{3}(t) = 0$

$\alpha_{1}\cdot 1 + \alpha_{2}\cdot t^{2}+ \alpha_{3}\cdot (3+3\cdot t+t^{2}) = 0$

$(\alpha_{1}+3\cdot \alpha_{3})\cdot 1+(\alpha_{2}+\alpha_{3})\cdot t^{2}+3\cdot \alpha_{3}\cdot t = 0$

The following system of linear equations is obtained:

$\alpha_{1}+3\cdot \alpha_{3} = 0$

$\alpha_{2} + \alpha_{3} = 0$

$3\cdot \alpha_{3} = 0$

Whose solution is $\alpha_{1} = \alpha_{2} = \alpha_{3} = 0$ , which means that the set of vectors is linearly independent.

The set of vectors A and C are linearly independent.

4 0

3 years ago

The largest telescope in the world is powerful enough to identify a penny that is 5 miles away. How many yards is this?

mojhsa [17]

We are given

The largest telescope in the world is powerful enough to identify a penny that is 5 miles away

it means that

distance =5 miles

we can change it into yards

we know that

1 mile=1760 yards

$d=5\times 1mile$

we can replace 1 mile

$d=5\times 1760 yards$

$d=8800 yards$

So, distance in yards is 8800 yards..........Answer

3 0

3 years ago