The height(in ft) of a golf ball hit in the air is given by the equation h(t) = -16t^2 + 128t, where t represents the time in se
conds after it was hit.
Part A) Find the maximum height reached by the golfball.
Part B) For how many seconds was the golfball in the air? Or how long did it take for the golfball to reach the ground?
2 answers:
The correct answer is 100 for both
Answer:
100 for both
Step-by-step explanation:
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A (-5,0) B (0,-2) C (-3,-4)
Answer:
2
Step-by-step explanation:
1. 20/10
2. divide numerator and denominator by 10
2. 2/1 = 2
Volume of B is 125×12=1500
3/4(x+21) = 10.5
0.75x+15.75 = 10.5
0.75x = -5.25
x = -7
Hope it helps : )
The answer is 343 if you add all together:)))
