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miv72 [106K]
3 years ago
15

Help plzzzzzz!!! The ratio of green marbles to total marbles in a bag is 2:9. The ratio of red marbles to total marbles in the s

ame bag is 1:3. Which of the following statements is true?
There are more red marbles in the bag.
There are more green marbles in the bag.
There is the same number of red and green marbles in the bag.
Mathematics
2 answers:
worty [1.4K]3 years ago
6 0
There are more green marbles
Nadusha1986 [10]3 years ago
5 0

Answer:

There are more red marbles in the bag

Step-by-step explanation:

2/9 = .2222 green

1/3 = .33333 red

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Let the no be x

ATQ

\\ \sf\longmapsto 2x+5=13

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\\ \sf\longmapsto 2x=8

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The value of y varies directly with x, and y = 18 when x = 12. find y when x = 132.
sveta [45]
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4 0
3 years ago
I have been stuck on this forever. Please help me
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5 0
3 years ago
Find the indicated nth term <br> show your solution 8,15,22,29,...,a18
Damm [24]

Answer:

127

Step-by-step explanation:

Hey there! :)

Let us find the 18th term — first, there are two main types of sequences.

  • Arithmetic Sequence — a sequence that has same difference or common difference.
  • Geometric Sequence — a sequence that has same ratio.

But if you notice, it cannot be geometric sequence because if we do ratio test, there are no common ratios.

Hence, it can only be arithmetic sequence.

<u>C</u><u>o</u><u>m</u><u>m</u><u>o</u><u>n</u><u> </u><u>D</u><u>i</u><u>f</u><u>f</u><u>e</u><u>r</u><u>e</u><u>n</u><u>c</u><u>e</u>

\displaystyle \large{a_{n + 1} - a_n = d}

d is our common difference.

a_n+1 is the next term of a_n.

Let's check the common difference!

15-8 = 7

22-15 = 7

29-22 = 7

Therefore, 7 is our common difference.

<u>G</u><u>e</u><u>n</u><u>e</u><u>r</u><u>a</u><u>l</u><u> </u><u>T</u><u>e</u><u>r</u><u>m</u><u>s</u><u> </u><u>o</u><u>f</u><u> </u><u>A</u><u>r</u><u>i</u><u>t</u><u>h</u><u>m</u><u>e</u><u>t</u><u>i</u><u>c</u><u> </u><u>S</u><u>e</u><u>q</u><u>u</u><u>e</u><u>n</u><u>c</u><u>e</u>

\displaystyle \large{a_n = a_1  + (n - 1)d}

We know that a1 is the first term of sequence which is 8.

Our common difference is 7.

We want to find the 18th term — therefore,

\displaystyle \large{a_{18} = 8  + (18 - 1)7} \\  \displaystyle \large{a_{18} = 8  + (17)7} \\  \displaystyle \large{a_{18} = 8  + 119} \\  \displaystyle \large{a_{18} = 127}

Therefore, the 18th term is 127.

4 0
3 years ago
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