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3 years ago

Given the two expressions shown below:

1 answer:

3 0

$\sqrt3\ is\ irrational\\\\\sqrt2\ is\ irrational\\\\\sqrt6\ is\ irrational\\\\therefore\\\\A.\ \sqrt3+\sqrt2\ is\ irrational\ and\ B.\ \sqrt3+\sqrt6\ is\ irrational$
Answer: Both are irrational.

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1. Emily is allowed to spend 60% of her allowance. The remaining 40% she deposits into her

kkurt [141]

Answer:

5

Explanation:

40x 200
—— ——
40 40
X=5

4 0

3 years ago

Read 2 more answers

HELP HELP <br> PLZ I WILL MARK YOU BRILL

Nikitich [7]

Answer:

1) 55 2)60-80 3)95 4)92.5(mean), 92.5 (median), 95 (mode) 5) the outlier greatly offsets the data as it is no where near the other data points.

Step-by-step explanation:

4 0

2 years ago

The sum of the tens digit and the hundreds digit of a number is three times the units digit. 1/5 of the sum of all three digits

Crazy boy [7]

Answer: The numbers are:

965

875

785

695

Step-by-step explanation:

We have a 3 digit number that can be written as:

a*100 + b*10 + c

Where a, b, and c are single-digit numbers.

a is the hundreds

b is the tens

c is the unit.

We know that:

"The sum of the tens digit and the hundreds digit of a number is three times the units digit."

a + b = 3*c

" 1/5 of the sum of all three digits is 1 less than the units digit."

(a + b + c)/5 = c - 1

Then we have the two conditions:

a + b = 3*c

(a + b + c)/5 = c - 1

From the first one, we can write:

(a + b)/3 = c

Replacing that in the other equation we get:

(a + b + a/3 + b/3)/5 = a/3 + b/3 - 1

(4/3)*(a + b)/5 = (a/3 + b/3) - 1

(4/15)*(a + b) = (a + b)/3 - 1

(4/15)*(a + b) - (a + b)/3 = - 1

-(1/15)*(a + b) = -1

a = 15 - b

Then we can give different values for b, and find the values of a and c, where a and c must be positive.

b = 9

a = 15 - 9 = 6

Then:

c = (9 + 6)/3 = 5

(notice that a + b = 15, then c will be always equal to 5, reggardless of the values of b and a).

This number will be:

695.

if b = 8, then:

a = 15 - 8 = 7

and c = 5, same as before.

the number is 785.

If b = 7, then:

a = 15 - 7 = 8

The number is 875

if b = 6, then:

a = 15 - 6 = 9

The number is:

965

4 0

2 years ago

Gravel is being dumped from a conveyor belt at a rate of 15 ft3/min, and its coarseness is such that it forms a pile in the shap

gayaneshka [121]

Answer:

0.13 ft/min

Step-by-step explanation:

We are given that

$\frac{dV}{dt}=15ft^3/min$

We have to find the increasing rate of change of height of pile when the pile is 12 ft high.

Let d be the diameter of pile

Height of pile=h

d=h

Radius of pile,r= $\frac{d}{2}=\frac{h}{2}$

Volume of pile= $\frac{1}{3}\pi r^2 h=\frac{1}{12}\pi h^3$

$\frac{dV}{dt}=\frac{1}{4}\pi h^2\frac{dh}{dt}$

h=12 ft

Substitute the values

$15=\frac{1}{4}\pi(12)^2\frac{dh}{dt}$

$\frac{dh}{dt}=\frac{15\times 4}{\pi(12)^2}$

$\frac{dh}{dt}=0.13ft/min$

7 0

3 years ago

Consider an experiment with sample space S 5 50, 1, 2, 3, 4, 5, 6, 7, 8, 96 and the events A 5 {0, 2, 4, 6, 8} B 5 {1, 3, 5, 7,

Brut [27]

Answer with Step-by-step explanation:

S={0,1,2,3,4,5,6,7,8,9}

A={0,2,4,6,8}

B={1,3,5,7,9}

C={0,1,2,3,4}

D={5,6,7,8,9}

a.A'=S-A

A'={0,1,2,3,4,5,6,7,8,9}-{0,2,4,6,8}

A'={1,3,5,7,9}

b.C'=S-C

C'={0,1,2,3,4,5,6,7,8,9}-{0,1,2,3,4}

C'={5,6,7,8,9}

c.D'=S-D

D'={0,1,2,3,4,5,6,7,8,9}-{5,6,7,8,9}

D'={0,1,2,3,4}

d. $A\cup B=$ {0,2,4,6,8} $\cup$ {1,3,5,7,9}

$A\cup B=$ {0,1,2,3,4,5,6,7,8,9}=S

e. $A\cup C$ ={0,2,4,6,8} $\cup$ {0,1,2,3,4}

$A\cup C$ ={0,1,2,3,4,6,8}

f. $A\cup D$ ={0,2,4,6,8} $\cup$ {5,6,7,8,9}

$A\cup D$ ={0,2,4,5,6,7,8,9}

8 0

3 years ago