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3 years ago

5

Nada hiked down a canyon and stopped each time she descended 1/2 mile to rest. She hiked a total of 4 sections. What is her over

all change in elevation?

1 answer:

zavuch27 [327]3 years ago

5 0

Answer:

She descended 2 miles

Step-by-step explanation:

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Convert the ratio 3:2 to a percentage

Black_prince [1.1K]

Answer:

150%

Step-by-step explanation:

1. Divide 3/2

2. Multiply by 100

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Pls explain how to do this

yulyashka [42]

find the value of x. if x is 2 for example multiply that 6 times to find the numerator. 2 x 2 x 2 x 2 x 2 x2 = 64. multiply that with 3 which is 192. now to find the denominator you are going to multiply 2 three times. 2 x 2 x2 = 8. now divide the denominator with the numerator which equals 8.

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3 years ago

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Brittany rents bicycles to tourists. She recorded the height (in cm) of each customer and the frame size (in cm) of the bicycle

bogdanovich [222]

Answer: -1

Step-by-step explanation:

Here is the complete question:

Brittany rents bicycles to tourists. She recorded the height (in cm) of each customer and the frame size (in cm) of the bicycle that customer rented. After plotting her results, Brittany noticed that the relationship between the two variables was fairly linear, so she used the data to calculate the following least squares regression equation for predicting bicycle frame size from the height of the customer: y'=1/3x + 1/3.

What is the residual of a customer with a height of 155 cm who rents a bike with a 51 cm frame?

The regression equation is given as:

y'=(1/3)x + (1/3)

Since the height is given as 155cm, x=155 cm

The predicted frame size,

y'=(1/3)x + (1/3)

y'=(1/3) × 155+ (1/3)

= 51 2/3 + 1/3

= 52

The observed frame size,

y=51

Residual = Observed y- predicted y

=51-52

= -1

The residual of a customer with a height of 155 cm who rents a bike with a 51 cm frame is -1.

4 0

3 years ago

Lab Assinent 1 Page 2 of 2 62:261, Fall 2019 are subsets of the 4. Let A = {2,3,4,7), B = {4,6,7), C = (3,5,7,8,9), and note tha

liubo4ka [24]

Answer:

a) AUB = {2,3,4,6,7}

b) $A\cap B=\{4,7\}$

c) $C'=\{1,2,4,6\}$

d) $C-B=\{3,5,8,9\}$

e) $(B\cup C)'=\{1,2\}$

Step-by-step explanation:

Consider the provided set.

A = {2,3,4,7}, B = {4,6,7}, C = {3,5,7,8,9}

Where A, B, and universe of discourse $U=\{x\in Z|1\leq x\leq 9\}$

So $U=\{1,2,3,4,5,6,7,8,9\}$

Part (A) Calculate AUB.

AUB represents the elements which are in A or in B or in both.

Therefore, AUB = {2,3,4,6,7}

Part (B) Find A n B

$A\cap B$ represent the elements which are in both the set A and B.

Therefore, $A\cap B=\{4,7\}$

Part (C) Find C'

$C'$ represent the elements that are not in C.

So the set C' contains all the element of set U except 3,5,7,8,9

Therefore, $C'=\{1,2,4,6\}$

Part (D) Find C-B

$C-B$ represent the elements of C which are not the elements of B.

So the set C-B contains all the element of set C except 7

Therefore, $C-B=\{3,5,8,9\}$

Part (E) Find (BUC)'

$(B\cup C)'$ represent all the elements of U which are not in B or in C or in both.

$B\cup C=\{3,4,5,6,7,8,9\}$

$(B\cup C)'=U-B\cup C=\{1,2\}$

Therefore, $(B\cup C)'=\{1,2\}$

5 0

3 years ago