Answer:
1st option
Step-by-step explanation:
< less than would have a empty circle
and 4 is less than
Answer:
Step-by-step explanation:
As for the angles of both triangles; they’re the same. The sides are 1:2.
I’m giving you formulas that are labeled: side a shortest
” b mid length
” c hypotenuse
angle α(alpha) opposite side a
” β(beta) ” ” b
” γ(gamma) ” ” c
A major formula for rt triangles is: a^2+b^2=c^2.
*Another is: a/sinα=b/sinβ=c/sinγ.
Remember α+β+γ=180°.
As for sides a&b use the above formula.
As for <ACB; the angle is γ which is a rt <.
Given: tan<x=5/2+1/2=6/2=3atan=71.565……….°=β. So α=18.44…….°. γ= rt angle.
To get the sides use the formulas at *.
Answer: 1: x^2 + 25 = 0 x=5
2: x^2 - 11x + 28 = 0 x=7 i think
3: x^2 + 8x + 16 = 0 x=-4
Step-by-step explanation:
Answer:
Step-by-step explanation:
If you call "5x-2x^2+1" an "equation," then you must equate 5x-2x^2+1 to 0:
5x-2x^2+1 = 0
This is a quadratic equation. Rearranging the terms in descending order by powers of x, we get:
-2x^2 + 5x + 1 = 0. Here the coefficients are a = -2, b = 5 and c = 1.
Use the quadratic formula to solve for x:
First find the discriminant, b^2 - 4ac: 25 - 4(-2)(1) = 25 + 8 = 33
Because the discriminant is positive, the roots of this quadratic are real and unequal.
-b ± √(discriminant)
Applying the quadratic formula x = --------------------------------
2a
we get:
-5 ± √33 -5 + √33
x = ----------------- = --------------------- and
2(-2) -4
-5 - √33
---------------
-4
Answer:
Joint variation says that:
if 
and 
then the equation is in the form of:
, where, k is the constant of variation.
As per the statement:
If x varies jointly as y and z
then by definition we have;
......[1]
Solve for k;
when x = 8 , y=4 and z=9
then
Substitute these in [1] we have;
⇒
Divide both sides by 36 we have;
Simplify:
⇒
to find z when x = 16 and y = 6
Substitute these value we have;
⇒
Multiply both sides by 9 we have;
Divide both sides by 12 we have;
12 = z
or
z = 12
Therefore, the value of z is, 12
