A. 48 = 12 + 20 + x
If you use this equation then you can do 12 + 20 = 32 and then you can do 48 - 32 = 16 so x = 16
Remark
I think you want us to do both 3 and 4
Three
QR is 4 points going left from the y axis + 2 points going right from the y axis.
QR = 6 units long.
RT is 4 units above the x axis and 3 units below the x axis
RT = 7 units long
TS = 3 units. For this one you just go from T to S. The graph really helps you. You just need to count.
Problem 4
You need to find the area of the combined figure. You could do it as a trapezoid, which might be the easiest way. I'll do that first.
Area = (b1 + b2)*h/2
Givens
B1 = QR = 6
B2 = UT + TS = 6 + 3 = 9
h = RT = 7
Area
Area = (6 + 9)*7/2
Area = 15 * 7 / 2
Area = 52.5
Comment
You could break this up into a rectangle + a triangle
Find the area of QRTU and add the Area of triangle RTS
<em>Area of the rectangle </em>= L * W
L = RT = 7
W = QR = 6
Area = 7 *6 = 42
<em>Area of the triangle</em> = 1/2 * B * H
B = TS = 3
H = RT =7
Area = 1/2 * 3 * 7
Area = 1/2 * 21
Area = 10.5
Total Area = 42 + 10.5 = 52.5 Both answers agree.
Answer:
yes, your right
Step-by-step explanation:
The answer is 640 because if you multiply the total student of 6h grade by 100 and divide by 30. You will get the total of student in the school
Answer:
12, 17, 24
Step-by-step explanation:
To find the first 3 terms, substitute n = 1, 2, 3 into the rule, that is
T₁ = 1² + 2(1) + 9 = 1 + 2 + 9 = 12
T₂ = 2² + 2(2) + 9 = 4 + 4 + 9 = 17
T₃ = 3² + 2(3) + 9 = 9 + 6 + 9 = 24
