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mihalych1998 [28]
3 years ago
6

Triangles Q R S and A B C are shown. The lengths of sides Q R and A B are 16 centimeters. The lengths of sides R S and B C are 2

4 centimeters. Angles Q R S and A B C are right angles. Sides Q S and A C are parallel and identical to each other and there is space in between the 2 triangles.
Is there a series of rigid transformations that could map ΔQRS to ΔABC? If so, which transformations could be used?

No, ΔQRS and ΔABC are congruent but ΔQRS cannot be mapped to ΔABC using a series rigid transformations.
No, ΔQRS and ΔABC are not congruent.
Yes, ΔQRS can be translated so that R is mapped to B and then rotated so that S is mapped to C.
Yes, ΔQRS can be translated so that Q is mapped to A and then reflected across the line containing QS.
Mathematics
2 answers:
just olya [345]3 years ago
9 0

Answer:

the actual answer is D

Step-by-step explanation:

they are congruent lol, i also took the unit test and got 100 on edge

olchik [2.2K]3 years ago
6 0

Answer:

b

Step-by-step explanation:

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Nataly_w [17]
\bf ~~~~~~ \textit{Simple Interest Earned Amount}
\\\\
A=P(1+rt)\qquad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to& \$950\\
r=rate\to 7\%\to \frac{7}{100}\to &0.07\\
t=years\to &5
\end{cases}
\\\\\\
A=950(1+0.07\cdot 5)\implies A=950(1.35)\implies A=1282.5
3 0
3 years ago
A 10 foot ladder is leaning against a wall. Call x the distance from the top of the ladder to the ground, and call y the distanc
liq [111]

-5.3\:\text{ft/s}

Step-by-step explanation:

We start by applying the Pythagorean theorem to the ladder, with its length L as the hypotenuse:

L^2 = 100\:\text{ft}^2 = x^2 + y^2

where x is the vertical distance from the top of the ladder to the ground and y is the horizontal distance from the bottom of the ladder to the wall. Taking the derivative of the above expression with respect to time, we get

0 = 2x\dfrac{dx}{dt} + 2y\dfrac{dy}{dt}

Solving for dx/dt, we get

\dfrac{dx}{dt} = -\left(\dfrac{y}{x}\right)\dfrac{dy}{dt} = -\left(\dfrac{\sqrt{L^2 - x^2}}{x}\right)\dfrac{dy}{dt}

We know that

\dfrac{dy}{dt} = 4\:\text{ft/s}

when x = 6 ft. So the rate at which the top of the ladder is going down is

\dfrac{dx}{dt} = -\left(\dfrac{\sqrt{100\:\text{ft}^2 - (6\:\text{ft})^2}}{6\:\text{ft}}\right)(4\:\text{ft/s})

\:\:\:\:\:\:\:= -5.3\:\text{ft/s}

The negative sign means that the distance x is decreasing as y is increasing.

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3 years ago
Evaluate the expression (ab)2 for a = 2 and b = 5. 100 50 20 625
kakasveta [241]

(ab)2

((2)(5.1005020625)2=?

((2)(5.1005020625)2=20.402

7 0
3 years ago
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The cruise control feature on a car is set to maintain a speed of 65 miles per hour. The car’s actual speed never varies by more
lyudmila [28]
(3x)65 would be the answer because the speed doesn't vary much
4 0
4 years ago
Find the least square number divisible by 5, 10, 15. (a) 100 (b) 625 (c) 900 (d) 225​
kkurt [141]

Answer:-

900

Verification:-

\\ \sf\longmapsto \dfrac{900}{5}=180

\\ \sf\longmapsto \dfrac{900}{10}=90

\\ \sf\longmapsto \dfrac{900}{15}=6

3 0
3 years ago
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