V+9

Determine the domain of the following graph:

dedylja [7]

Answer:

Domain: -5, -3, -2, 1, 3

Step-by-step explanation:

Find all the points on the x-axis that line up with the line shown on the graph.

8 0

2 years ago

Use synthetic division to find the result when x^4-2x^2-4x-48 is divided by x-3

just olya [345]

Answer: it’s x^3+3x^2+7x+17+3/x-3

Sorry ab the handwriting lol

Step-by-step explanation:

7 0

2 years ago

Find [-4/5]×3/7×15/16×[-14/9]

dangina [55]

The given expression is $\frac{-4}{5} \times \frac{3}{7} \times \frac{15}{16} \times (\frac{-14}{9})$ .

We need to simplify the given expression.

<h3>What is a rational number?</h3>

In mathematics, a rational number is a number that can be expressed as the quotient or fraction p/q of two integers, a numerator p and a non-zero denominator q.

Now group the rational numbers $(\frac{-4}{5}\times \frac{15}{16} ) \times (\frac{3}{7}\times (\frac{-14}{9}))$

$=(\frac{-4}{16}\times \frac{15}{5} ) \times (\frac{3}{9}\times (\frac{-14}{7}))$

$=(\frac{-1}{4}\times \frac{3}{1} ) \times (\frac{1}{3}\times (\frac{-2}{1}))$

$=(\frac{-3}{4} ) \times (\frac{-2}{3})=\frac{1}{2}$

Therefore, the simplified value of the given expression is $\frac{1}{2}$ .

To learn more about the rational numbers visit:

brainly.com/question/17450097.

#SPJ1

8 0

2 years ago

Please help will do anything thank you

kifflom [539]

Answer:

Step-by-step explanation:

a). Stock price arranged as arithmetic sequence will be,

5, 8, 11, 14

b). Since, explicit formula of an arithmetic sequence is given by,

$a_n=a+(n-1)d$

Here, $T_n$ = nth term of the sequence

a = first term

n = number of term

d = common difference

From the table attached,

First term of the sequence 'a' = 5

Common difference 'd' = 8 - 5 = 3

Therefore, explicit formula for the given sequence will be,

$a_n=5+3(n-1)$

$a_n=2+3n$

c). Slope intercept form of the equation will be,

y = 3x + 2

d). Input out values for the graph of the given equation,

x 0 1 2 3

y 2 5 8 11

By using this data we can graph the line.

7 0

3 years ago

AABC has vertices at A(1, -9), B(8,0), and C(9,-8).

Rainbow [258]

Check the picture below.

$~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill~ \\\\[-0.35em] ~\dotfill\\\\ A(\stackrel{x_1}{1}~,~\stackrel{y_1}{-9})\qquad B(\stackrel{x_2}{8}~,~\stackrel{y_2}{0}) ~\hfill AB=\sqrt{[ 8- 1]^2 + [ 0- (-9)]^2} \\\\\\ AB=\sqrt{7^2+(0+9)^2}\implies AB=\sqrt{7^2+9^2}\implies \boxed{AB=\sqrt{130}} \\\\[-0.35em] ~\dotfill$

$B(\stackrel{x_1}{8}~,~\stackrel{y_1}{0})\qquad C(\stackrel{x_2}{9}~,~\stackrel{y_2}{-8}) ~\hfill BC=\sqrt{[ 9- 8]^2 + [ -8- 0]^2} \\\\\\ BC=\sqrt{1^2+(-8)^2}\implies \boxed{BC=\sqrt{65}}$

now, we could check for the CA distance, however, we already know that AB ≠ BC, so there's no need.

6 0

2 years ago