All categories

2 years ago

Rewrite the expression as a product using the GCF and distributive property. 27 + 45

Mathematics

2 answers:

vovangra [49]2 years ago

3 0

Step-by-step explanation:

GCF of 27 and 45 is 9

iren2701 [21]2 years ago

3 0

Answer: 9 (3+5)

Step-by-step explanation:

The GFCF of these two numbers is 9 as they can both be divided by it

Distributive property form is when you place the GFC outside parenthesis so that the equation can be multiplied in order to show the original equation and dividing the numbers by the GCF so that it does not give you a larger number than what you started with

27/9=3 + 45/9=5

So, keeping this in mind the distributive property form would be 9(3+5)

Answer 9(3+5)

You might be interested in

8-102.

PIT_PIT [208]

a. The speed is represented by 7 miles an hour

b. f(t)=7t

c. 28 miles

5 0

3 years ago

There are 10 cranberry and 15 strawberry juices. You randomly pick two juices. What's the probability you'll get two strawberry

lorasvet [3.4K]

Answer:

7/20

Explanation:

The theoretical probability, P (A), of an event, A, is:

P(A) = number of outcomes of event A / total number of possible outcomes

For 10 cranberry and 15 strawberry juices, the number of outcomes for two strawberry juices are:

Combination of 15 strawberry juices chosen in two:

$C^{15}_{2}=\frac{15!}{(15-2)!(2!)}=\frac{15!}{13!2!}=\frac{15\times 14}{2}=105$

The total number of possible outcomes is:

Combination of 25 juices chosen in two:

$C^{25}_{2}=\frac{25!}{(25-2)!(2!)}=\frac{25!}{23!2!}=\frac{25\times 24}{2}=300$

Thus, the probability of randomly picking two strawberry juices is:

P (two strawberry juices) = 105/300 = 7/20

Note that you can obtain it as the product of the probabilities that the first juice is a strawberry juice and the second juice is also strawberry juice:

$15/25\times 14/24=(15\times 25)/(14\times 24)=210/600=7/20$

5 0

2 years ago

What is 18/25 simplified

Alekssandra [29.7K]

18/25 is already simplified. There is no number that can go in both 18 and 25.

7 0

2 years ago

Read 2 more answers

Give all solutions if the nonlinear system of equations, including those with no real complex components.

konstantin123 [22]

$\left\{\begin{array}{ccc}y=x^2+6x\\4x-y=-24\end{array}\right\\\\substitute:\\\\4x-(x^2+6x)=-24\\\\4x-x^2-6x+24=0\\\\-x^2-2x+24=0\\\\a=-1;\ b=-2;\ c=24\\\\\Delta=b^2-4ac$

$\Delta=(-2)^2-4\cdot(-1)\cdot24=4+96=100\\\\x_1=\frac{-b-\sqrt\Delta}{2a};\ x_2=\frac{-b+\sqrt\Delta}{2a}\\\\\sqrt\Delta=\sqrt{100}=10\\\\x_1=\frac{2-10}{2\cdot(-1)}=\frac{-8}{-2}=4;\ x_2=\frac{2+10}{2\cdot(-1)}=\frac{12}{-2}=-6\\\\y_1=4^2+6\cdot4=16+24=40;\ y_2=(-6)^2+6\cdot(-6)=36-36=0\\\\Answer:\\x=4\ and\ y=40\ or\ x=-6\ and\ y=0$

4 0

3 years ago

Read 2 more answers

If it takes 6 hours for a plane to travel 720km with a tail wind and 8 hours to make the return trip with a head wind. Find the

denis-greek [22]

The speed of wind and plane are 105 kmph and 15 kmph respectively.

<u>Solution:</u>

Given, it takes 6 hours for a plane to travel 720 km with a tail wind and 8 hours to make the return trip with a head wind.

We have to find the air speed of the plane and speed of the wind.

Now, let the speed wind be "a" and speed of aeroplane be "b"

And, we know that, distance = speed x time.

$\text { Now, at tail wind } \rightarrow 720=(a+b) \times 6 \rightarrow a+b=\frac{720}{6} \rightarrow a+b=120 \rightarrow(1)$

Now at head wind → $720=(a-b) \times 8 \rightarrow a-b=\frac{720}{8} \rightarrow a-b=90 \rightarrow(2)$

So, solve (1) and (2) by addition

2a = 210

a = 105

substitute a value in (1) ⇒ 105 + b = 120

⇒ b = 120 – 105 ⇒ b = 15.

Here, relative speed of plane during tail wind is 120 kmph and during head wind is 90 kmph.

Hence, speed of wind and plane are 105 kmph and 15 kmph respectively.

6 0

3 years ago