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11111nata11111 [884]
3 years ago
15

Sarah biked 13 miles south from her house to the library. Then she turned and biked 10 miles

Mathematics
1 answer:
Tanya [424]3 years ago
4 0

Answer:

16.40

Step-by-step explanation:

use Pythagorean theorem

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The staff commute to work in different ways 2/5 drive, 4/15 catch the bus and 1/3 cycle
gavmur [86]

Answer:

2/5, 1/3 4/15

Step-by-step explanation:

3x2/5=6/15

5x1/3=5/15

4/15

4 0
3 years ago
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Chứng minh mệnh đề sau bằng phương pháp phản chứng:
GalinKa [24]

Answer:

Which language is this ?????

4 0
3 years ago
Can somebody prove this mathmatical induction?
Flauer [41]

Answer:

See explanation

Step-by-step explanation:

1 step:

n=1, then

\sum \limits_{j=1}^1 2^j=2^1=2\\ \\2(2^1-1)=2(2-1)=2\cdot 1=2

So, for j=1 this statement is true

2 step:

Assume that for n=k the following statement is true

\sum \limits_{j=1}^k2^j=2(2^k-1)

3 step:

Check for n=k+1 whether the statement

\sum \limits_{j=1}^{k+1}2^j=2(2^{k+1}-1)

is true.

Start with the left side:

\sum \limits _{j=1}^{k+1}2^j=\sum \limits _{j=1}^k2^j+2^{k+1}\ \ (\ast)

According to the 2nd step,

\sum \limits_{j=1}^k2^j=2(2^k-1)

Substitute it into the \ast

\sum \limits _{j=1}^{k+1}2^j=\sum \limits _{j=1}^k2^j+2^{k+1}=2(2^k-1)+2^{k+1}=2^{k+1}-2+2^{k+1}=2\cdot 2^{k+1}-2=2^{k+2}-2=2(2^{k+1}-1)

So, you have proved the initial statement

4 0
4 years ago
There are 25 students in a class at the beginning of the school year and the average number of siblings for each student is thre
Zigmanuir [339]

Answer:  Yes. The new average is 3

<u>Step-by-step explanation:</u>

25 students at 3 siblings each = 75 siblings

26 students has 75 siblings + 8 siblings = 83 siblings

New average is 83 siblings ÷ 26 students = 3.19 siblings per students

5 0
3 years ago
Calculus A hard problem help please
dexar [7]
∑x = 1 + 2 + 3 + 4 + 5 + 6 = 21
∑y = 8 + 3 + 0 + 1 + 2 + 1 = 15
∑x^2 = 1 + 4 + 9 + 16 + 25 + 36 = 91
∑y^2 = 64 + 9 + 0 + 1 + 4 + 1 = 79
∑xy = 8 + 6 + 0 + 4 + 10 + 6 = 34

r = (n∑xy - ∑x∑y)/(sqrt(n∑x^2 - (∑x)^2)*sqrt(n∑y^2 - (∑y)^2)) = (6(34) - 21(15))/(sqrt(6(91) - (21)^2)*sqrt(6(79) - (15)^2)) = (204 - 315)/(sqrt(546 - 441)*sqrt(474 - 225)) = -111/(sqrt(105)*sqrt(249)) = -111/(10.25*15.78) = -111/161.7 = -0.68

3 0
3 years ago
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