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3 years ago

Use the change of base formula to approximate the solution to log0.515 = 1 – 2x. Round to the nearest hundredth.

Mathematics

2 answers:

algol [13]3 years ago

5 0

Answer:

2.45

Step-by-step explanation:

ANEK [815]3 years ago

5 0

Answer:

its 2.45

Step-by-step explanation:

got it right on the assignment

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Find the midpoint of the line segment joining the points (−2,−1) and (−8,4).

Temka [501]

Answer:

(-5, 1.5)

Step-by-step explanation:

(-2 ,-1) ; (-8 , 4)

Midpoint = $(\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})\\\\$

$=(\frac{-2-8}{2}, \frac{-1+4}{2})\\\\=(\frac{-10}{2},\frac{3}{2})\\\\=(-5 , 1.5)$

8 0

3 years ago

3x° 30° x = degrees dhdjdjdjdjfj

yuradex [85]

Answer:

x=10

Step-by-step explanation:

since the angles seem similar they're most likely to be the same but since its 3x and you have to find the value of x then we will do 3 x ?=30, which is 10. if you want to check there is one way, since the angle on a straight line is 180 you can do 180 - 30 =150 which will be the unknown value next to the given angle. Since the unknown angle is on the line with the 150 degree angle we can do 180 - 50 to get the unknown angle (3x) which is 30. So in conclusion x will be 10

5 0

3 years ago

Read 2 more answers

Ellie made a cube-shaped cardboard box with side-length s. The area of cardboard she used is given by the formula A = 6s2, wher

xenn [34]

The correct question is
Ellie made a cube-shaped cardboard box with side-length s. The area of cardboard she used is given by the formula A = 6s2, where s represents the side length of the cube.

Which equation correctly solves the formula for s?

we know that
A = 6s²---------> clear the variable s
s²=A/6------> applying square root both members
s=√(A/6)--------> s=(1/6)*√(6*A)

the answer is
s=(1/6)*√(6*A)

4 0

3 years ago

PLEASE HELP ASAP I REALLY NEED HELP AND EXPLINATION I WILL GIVE BRAINLIEST!!

Lady bird [3.3K]

The given data can be completed in a tabular form by using the given data

points row and column totals.

Responses:

Part A: The percentage of the respondents that do not like both hamburgers and burritos is approximately 26.34%

Part B: The marginal relative frequency is approximately 0.537

Part C: The data point that has strongest association of its two factors is the data point for the respondents that like hamburger but do not like burritos which is 81

<h3>Methods used for the calculations:</h3>

The given data is presented as follows;

$\begin{tabular}{|l|c|c|c|}&Like hamburgers&Does not like hamburgers& Total\\Likes burritos&29&41&\\Does not like burritos &&54&135\\Total&110&&205\end{array}\right]$

Number of respondents that do not like burritos = 135 - 54 = 81

The total number of respondents that do not like hamburgers = 41 + 54 = 95

The total number of respondents that like burritos = 29 + 41 = 70

Part A:

Number of respondents that do not like both hamburgers and burritos = 54

The percentage of the survey that do not like both hamburgers and burritos (H∩B)' is therefore;

$Percentage \ of \ (H \cap B)' = \mathbf{\dfrac{54}{205} \times 100} = 26.\overline{34146} \ \% \approx 26.34 \ \%$

The percentage that do not like both hamburgers and burritos is approximately 26.34%

Part B:

Marginal relative frequency of all customers that like hamburgers.

$Marginal \ relative \ frequency = \mathbf{\dfrac{Total \ number \ of \ customers \ that \ like \ hamburgers}{Grand \ total \ of \ repondents \ in \ the \ survey}}$

Therefore;

$Marginal \ relative \ frequency = \dfrac{110}{205} = \dfrac{22}{41} \approx \underline{ 0.537}$

Part C:

The completed table is presented as follows;

$\begin{tabular}{|l|c|c|c|}&Like hamburgers&Does not like hamburgers&Total\\Likes burritos&29&41&70\\Does not like burritos&81&54&135\\Total&110&95& 205\end{array}\right]$

The conditional relative frequencies are presented as follows;

$Conditional \ relative \ frequency \ (row)\\\begin{tabular}{|l|c|c|c|}& Cond. Rel. Frequency&&Total\\Likes burritos&29 \div 70 \approx 0.414&41 \div 70 \approx 0.586 &70 \div 70 = 1 \\Does not like burritos&81 \div 135 = 0.6&54 \div 135= 0.4&135 \div 135 = 1\end{array}\right]$

$Conditional\ Relative \ Frequencies \ (column)\\\begin{tabular}{|l|c|c|c|}&Like hamburgers&Does not like hamburgers\\Likes burritos&29 \div 110 \approx 0.263&41 \div 95 \approx 0.432\\Does not like burritos&81 \div 110 \approx 0.763&54 \div 95 \approx 0.568 \\&110 \div 110 = 1&95 \div 95 = 1\end{array}\right]$

A strong association variables relates to how much a variable depends on another variable, which is the level of relationship.

Based on the above relative frequency tables, we have that the data point

for those that like hamburger (29, 81) is such that only approximately 26.3%

of those that like hamburgers like burritos, while 76.3% that like hamburger

do not like burritos, which can be interpreted as follows;

Majority of customers that like hamburgers (76.3%) do not like burritos

Therefore;

A data point that has the strongest association is the data point for the customers that like hamburgers and do not like burritos which is 81.

Learn more conditional relative frequency table

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3 0

2 years ago

Can someone help me again please:(

uranmaximum [27]

Answer:

C. 29sqrt(5)

Step-by-step explanation:

Since sqrt(45) is sqrt(9*5), then we can take the 9 out and we get 11*3sqrt(5)-4sqrt(5). This can be rewritten as 33sqrt(5) - 4sqrt(5). Combining like terms, we get 29sqrt(5)

6 0

3 years ago

Read 2 more answers