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REY [17]
3 years ago
15

A train left Podunk and traveled north at 75 km/h. Two hours later, another train left Podunk and traveled in the same direction

at 100 km/h. How many hours had the first train traveled when the second train overtook it?​
Mathematics
1 answer:
Andreyy893 years ago
6 0
Answer:

8 hours

Steps:

Train 1:

Hours: 1, 2, 3, 4, 5, 6, 7, 8

Miles: 75, 150, 225, 300, 375, 450, 525, 600

Train 2:

Hours: 1, 2, 3, 4, 5, 6, 7, 8

Miles: 0, 0, 100, 200, 300, 400, 500, 600
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Multiply y^2-16/2y . 5y/y-4
alisha [4.7K]
So, first we multiply the fraction by using the formula a/b times c/d= a times c/b times d
=(y^2-16) times 5y/2y(y-4)
Now, we cancel the common factor y
=(y^2-16) times 5/2(y-4)
Now, we factor 5(y^2-16)
We factor (y^2-16) first
y^2-16
Rewrite 16 as 4^2
y^2-4^2
Now, apply the formula x^2-y^2=(x+y)(x-y)
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Cancel the common factor y-4
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5 0
3 years ago
Help Asap plz!!!! Thx Give 2<br>0 points
Arisa [49]

Answer:

(1,2) is a solution to both equations

Step-by-step explanation:

To determine if (1,2) is a solution to both equations, substitute into the equation and see if it is true

2x+y =4

2(1) + 2 =4

2+2 =4

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true


y =3x-1

2 = 3(1) -1

2 =3-1

2=2

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Since both statements are true

(1,2) is a solution to both equations

4 0
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Evaluate the expression <br><br> (x + 3)(y - 2) , if x = -2, and y= 6
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Answer:

The answer is 4

Step-by-step explanation:

Given,

x=-2,\,y=6

Now, the expression

∴(x+3)(y-2)\\=>(-2+3)(6-2)\\=>(1)(4)\\4

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3 years ago
A=1/2(a+b)h solve for h
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