Looking at the image I have attached (with MN being the midsegment of the trapezoid), For any PQ with P and Q lying on the bases of the trapezoid there exists ON with O being the point of intersection between PQ and MN. ON must be parallel to PC because ON is part of MN and PC is a part of DC, and MN and DC are parallel. And N must be the midpoint of CB because MN is the midsegment of the trapezoid, so MN must bisect CB. And since ON is parallel to PC and bisects CB, that means it is a midsegment of QBCP and must bisect PQ.
Answer:
She saved $1,470 for seven years.
Step-by-step explanation:
Answer:
3. m<GHF= 90 degrees
4. m<DGH= 45 degrees
5. HF=5
6. DE=50
Step-by-step explanation:
3. The measure of angle DGF and EFG are 45 degrees each and 45+45 is 90 degrees. When you subtract 90 from 180, you get 90.
4. A square is also a rectangle and a rectangle has four right angles and it is a rhombus and the diagonals bisect the angles. This means that angle DGH is half of angle DGF and 90/2=45.
5. The diagonals of a square are congruent so it is also 5.
6. You use the Pythagorean Theorem and 5^2 + 5^2=50
It is y=1/4x because when a problem is linear it has an exponent of 1
Answer:
90 km an hour.
Step-by-step explanation:
