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3 years ago

Without graphing, classify each system

Mathematics

1 answer:

Alik [6]3 years ago

3 0

Answer:

Inconsistent

Step-by-step explanation:

None

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Which is equivalent to 3 cube root 125

aleksklad [387]

Do you mean $3 \sqrt[3]{125}$ or $\sqrt[3]{125}$
remember that $\sqrt[n]{x^m}=x^\frac{m}{n}$
resolve the $\sqrt[3]{125}$ part first $\sqrt[3]{125}=$ $\sqrt[3]{5^3}=$ $5^\frac{3}{3}=$ $5^1=$ $5$

so
$3 \sqrt[3]{125}=3*5=15$ or $\sqrt[3]{125} =5$ not sure which one you mean

7 0

3 years ago

Read 2 more answers

Your brother ordered some pens on the internet. It cost 2$ for each pen and the shipping fee is 3$. If your brother paid a total

Mars2501 [29]

Answer:

10pens

Step-by-step explanation:

23-3=20

20÷2=10

5 0

3 years ago

Louisa’s savings change by -$6 each time she goes bowling. In all, it changed by -$66 during the summer. How many times did she

Sav [38]

Answer: She went $11$ times during the summer.

Step-by-step explanation:

If Louisa's savings change by $-6$ each time she goes bowling and it went to $-66$ , that means that Louisa went another $11$ times.

$\frac{1}{11}$

So therefore your answer would be 11.

6 0

2 years ago

Convert each of the following estimates of useful life to a straight-line depreciation rate, stated as a percentage: (a) 10 year

Rzqust [24]

Answer:

a.10 years 1 / 10 x 100 10% per year

b. 8 years 1 / 8 x 100 12.5% per year

c. 25 years 1 / 25 x 100 4% per year

d. 40 years 1 / 40 x 100 2.5% per year

e. 5 years 1 / 5 x 100 20% per year

f. 4 years 1 / 4 x 100 25% per year

g. 20 years 1 / 20 x 100 5% per year

Step-by-step explanation:

Under straight line method of depreciation, equal amount of the depreciation is reduced throughout the useful life of the asset. Using the following formula:

<u>Straight line depreciation rate = 1 / Useful Life x 100 </u>

So:

a.10 years 1 / 10 x 100 10% per year

b. 8 years 1 / 8 x 100 12.5% per year

c. 25 years 1 / 25 x 100 4% per year

d. 40 years 1 / 40 x 100 2.5% per year

e. 5 years 1 / 5 x 100 20% per year

f. 4 years 1 / 4 x 100 25% per year

g. 20 years 1 / 20 x 100 5% per year

7 0

4 years ago

A rock is thrown vertically upward from the surface of an airless planet. It reaches a height of s = 120t - 4t2 meters in t seco

12345 [234]

Answer:

Step-by-step explanation:

Given that a rock is thrown vertically upward from the surface of an airless planet. It reaches a height of $s(t) = 120t - 4t^2$

where t is expressed in seconds

The rock goes upto a height where the velocity becomes 0 and then it starts falling down by gravity

Velocity at time t = s'(t) = $120-8t$

This becomes 0 when t =15 seconds

Hence at 15th second the rock starts falling and upto

s(15) = $120(15)-4(15^2)\\= 900$ metres high it goes

The time taken to reach highest point is = 15 seconds.

6 0

4 years ago