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3 years ago

Find the exact value of x.

Mathematics

2 answers:

Eddi Din [679]3 years ago

8 0

Answer:

x. 0.98 value all yee uuu

Ierofanga [76]3 years ago

4 0

Step-by-step explanation:

there is no equation but if u let me know I can be able to help u out!

You might be interested in

Which equations show you how to find 16-9?

Pie

The correct answer is B.
16-9=7
So, 7+9=16.

If we add to 9 only 1 (out of those 7) we have then 10, remaining 6.
9+1=10

Now, if to 10 we add the remaining 6 we will have the final 16.
10+6=16

16-9=7 <=> 9+7=16 <=> (9+1)+6=16

5 0

3 years ago

Graph the equations to solve the system. y=-1/2x y=-1/3x+1

Pachacha [2.7K]

Answer:

The solution to the system of equations is (-6, 3)

Step-by-step explanation:

Plot both lines on a graph, find where they intersect IF they even intersect at all like in this case, and boom there's your answer. Hope that helps and have a good rest of your day.

3 0

4 years ago

Which of the following is the equation of a line perpendicular to the line y = -10x + 1, passing through the point (5,7)?

Viktor [21]

Line 1;
y=-10x+1
Gradient m= -10
Gradient of line 2= 1/10
$\frac{y-5}{x-7} = \frac{1}{10}$
y-5= $\frac{1}{10} {x-7}$
y-5= $\frac{1}{10} x- \frac{7}{10}$
y= $\frac{1}{10} x- \frac{43}{10}$

6 0

3 years ago

Read 2 more answers

Matt and Anna Killian are frequent fliers on Fast-n-Go Airlines. They often fly between two cities that are a distance of 1980

Ymorist [56]

Answer:

y (plane speed) 400 miles/hr

x (wind speed) 40 miles/hr

Step-by-step explanation:

going into the wind make the plane flew 5,5 hours to get 1980 miles, implies the real travel speed was

1980 / 5,5 = 360 miles/hours, and at the same time is the result of:

speed plane (y) in direction A to B plus wind speed (x) in direction B to A. Notice opposites direction speed, so we have:

y + (-x) = 360 (1)

The return fly took 4,5 hours so 1980/4,5 = 440 miles/ hours as the result

Y + x = 440 (2)

We have a two equation with two variables system, It could be solved for any of the procedures. We will use the substitution method.

From equation (1) y + (-x) = 360 y - x = 360 y = 360 + x (1)

In the second equation

y + x = 440 then we replace y for its value as function of x

(360 + x ) + x = 440

Solving for x 360 + 2x = 440 or 2x = 440 – 360

x (440 - 360)/2

x = 40 miles/hr

X (wind speed ) = 40 miles/hr

And replacing the value of x in eq. (1) y = 360 + 40 = 400

Y (plane speed) = 400 miles /hr

3 0

3 years ago

While conducting a test of modems being manufactured, it is found that 10 modems were faulty out of a random sample of 367 modem

Kitty [74]

Answer:

We conclude that this is an unusually high number of faulty modems.

Step-by-step explanation:

We are given that while conducting a test of modems being manufactured, it is found that 10 modems were faulty out of a random sample of 367 modems.

The probability of obtaining this many bad modems (or more), under the assumptions of typical manufacturing flaws would be 0.013.

Let p = population proportion.

So, Null Hypothesis, $H_0$ : p = 0.013 {means that this is an unusually 0.013 proportion of faulty modems}

Alternate Hypothesis, $H_A$ : p > 0.013 {means that this is an unusually high number of faulty modems}

The test statistics that would be used here One-sample z-test for proportions;

T.S. = $\frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion faulty modems= $\frac{10}{367}$ = 0.027

n = sample of modems = 367

So, the test statistics = $\frac{0.027-0.013}{\sqrt{\frac{0.013(1-0.013)}{367} } }$

= 2.367

The value of z-test statistics is 2.367.

Since, we are not given with the level of significance so we assume it to be 5%. Now at 5% level of significance, the z table gives a critical value of 1.645 for the right-tailed test.

Since our test statistics is more than the critical value of z as 2.367 > 1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that this is an unusually high number of faulty modems.

6 0

4 years ago