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3 years ago

7

Help with this quistion

1 answer:

yan [13]3 years ago

3 0

Answer:

3 root 7 the 1st one

Step-by-step explanation:

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The coordinates of the vertices of a polygon are (-2, 1). (-3, 3), (-1, 5), (2, 4), and (2, 1). What is the perimeter of the pol

kobusy [5.1K]

Answer:

$15.2\ units$

Step-by-step explanation:

step 1

Plot the vertices of the polygon to better understand the problem

we have

$A(-2, 1). B(-3, 3), C(-1, 5), D(2, 4),E(2, 1)$

using a graphing tool

The polygon is a pentagon (the number of sides is 5)

see the attached figure

The perimeter is equal to

$P=AB+BC+CD+DE+AE$

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

step 2

<em>Find the distance AB</em>

$A(-2, 1). B(-3, 3)$

substitute in the formula

$d=\sqrt{(3-1)^{2}+(-3+2)^{2}}$

$d=\sqrt{(2)^{2}+(-1)^{2}}$

$d_A_B=\sqrt{5}=2.24\ units$

step 3

<em>Find the distance BC</em>

$B(-3, 3), C(-1, 5)$

substitute in the formula

$d=\sqrt{(5-3)^{2}+(-1+3)^{2}}$

$d=\sqrt{(2)^{2}+(2)^{2}}$

$d_B_C=\sqrt{8}=2.83\ units$

step 4

<em>Find the distance CD</em>

$C(-1, 5), D(2, 4)$

substitute in the formula

$d=\sqrt{(4-5)^{2}+(2+1)^{2}}$

$d=\sqrt{(-1)^{2}+(3)^{2}}$

$d_C_D=\sqrt{10}=3.16\ units$

step 5

<em>Find the distance DE</em>

$D(2, 4),E(2, 1)$

substitute in the formula

$d=\sqrt{(1-4)^{2}+(2-2)^{2}}$

$d=\sqrt{(-3)^{2}+(0)^{2}}$

$d_D_E=\sqrt{9}\ units$

$d_D_E=3\ units$

step 6

<em>Find the distance AE</em>

$A(-2, 1).E(2, 1)$

substitute in the formula

$d=\sqrt{(1-1)^{2}+(2+2)^{2}}$

$d=\sqrt{(0)^{2}+(4)^{2}}$

$d_A_E=\sqrt{16}\ units$

$d_A_E=4\ units$

step 7

Find the perimeter

$P=AB+BC+CD+DE+AE$

substitute the values

$P=2.24+2.83+3.16+3+4=15.23\ units$

Round to the nearest tenth of a unit

$P=15.2\ units$

6 0

2 years ago

The rate of change (dP/dt), of the number of people on an ocean beach is modeled by a logistic differential equation. The maximu

Kazeer [188]

Answer:

$\frac{dP}{dt} = 2.4P(1 - \frac{P}{1200})$

Step-by-step explanation:

The logistic differential equation is as follows:

$\frac{dP}{dt} = rP(1 - \frac{P}{K})$

In this problem, we have that:

$K = 1200$ , which is the carring capacity of the population, that is, the maximum number of people allowed on the beach.

At 10 A.M., the number of people on the beach is 200 and is increasing at the rate of 400 per hour.

This means that $\frac{dP}{dt} = 400$ when $P = 200$ . With this, we can find r, that is, the growth rate,

So

$\frac{dP}{dt} = rP(1 - \frac{P}{K})$

$400 = 200r(1 - \frac{200}{1200})$

$166.67r = 400$

$r = 2.4$

So the differential equation is:

$\frac{dP}{dt} = rP(1 - \frac{P}{K})$

$\frac{dP}{dt} = 2.4P(1 - \frac{P}{1200})$

3 0

2 years ago

What number should go in the space?<br> Multiplying by 1.45 is the same as increasing by _____%.

Reptile [31]

Answer:

you would way nothing

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

In 2018, the number of students at The Villages High School was 975 and is increasing at a rate of 2.5% per year. Write and use

avanturin [10]

Answer:

$A(t)=975(1.025)^t$

In 2025,the number of students at the villages high school=1159

Step-by-step explanation:

We are given that in 2018

Number of students at the villages high school=975

Increasing rate,r=2.5%=0.025

We have to write and use of exponential growth function to project the populating in 2025.

$A_0=975,t=0$

According to question

Number of students at the villages high School is given by

$A(t)=A_0(1+r)^t$

Substitute the values

$A(t)=975(1+0.025)^t=975(1.025)^t$

t=7

Substitute the value

Then, the number of students at the villages high school in 2025

$A(7)=975(1.025)^7=1158.96\approx 1159$

8 0

2 years ago

Read 2 more answers

What math terms is -3 categories in

oksian1 [2.3K]

Idek i need points man

4 0

3 years ago