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lanation for a 7th grader
Working together, two ants named Aran and Beatrice can build an ant hill
in 10 hours. Aran and Charlie can build the ant hill in 12 hours. Beatrice
and Charlie can build the ant hill in 15 hours. How long, in hours, will it
take to build the ant hill if Aran, Beatrice, and Charlie work together?
Working together, two ants named Aran and Beatrice can build an ant hill
in 10 hours. Aran and Charlie can build the ant hill in 12 hours. Beatrice
and Charlie can build the ant hill in 15 hours. How long, in hours, will it
take to build the ant hill if Aran, Beatrice, and Charlie work together?
1 answer:
Answer:
They complete the hill in 8 hours
Step-by-step explanation:
We will need to solve these equations with a system of equations, so we need to isolate one variable in one of the equations and then replace it with another equation. After this, this means that Beatrice alone would construct the hill in 24 hours and Charlie 40. So, after finding the value A we will need to add A with B and C. This would get us . We will then divide
. This will leave with 8h.
A= 7/120h
C=1/40h
B= 1/24h
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Answer:
We conclude that the mean duration of 15-sided union rugby games has decreased after the meeting.
Step-by-step explanation:
We are given that Before the meeting, the mean duration of the 15-sided rugby game time was 3 hours, 5 minutes, that is, 185 minutes.
A random sample of 36 of the 15-sided rugby games after the meeting showed a mean of 179 minutes with a standard deviation of 12 minutes.
Let = <em><u>mean duration of 15-sided union rugby games after the meeting.</u></em>
So, Null Hypothesis, :
185 minutes {means that the mean duration of 15-sided union rugby games has increased or remained same after the meeting}
Alternate Hypothesis, :
< 185 minutes {means that the mean duration of 15-sided union rugby games has decreased after the meeting}
The test statistics that would be used here <u>One-sample t test statistics</u> as we don't know about the population standard deviation;
T.S. = ~
where, = sample mean duration of 15-sided union rugby games = 179 min
s = sample standard deviation = 12 minutes
n = sample of 15-sided rugby games = 36
So, <u><em>the test statistics</em></u> = ~
= -3
The value of t test statistics is -3.
<u>Now, at 1% significance level the t table gives critical value of -2.437 at 35 degree of freedom for left-tailed test.</u>
Since our test statistic is less than the critical value of t as -3 < -2.437, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u>we reject our null hypothesis</u>.
Therefore, we conclude that the mean duration of 15-sided union rugby games has decreased after the meeting.
Answer:
Step-by-step explanation:
Use DESMOS to make the graph. You can either rearrange the equation to put it in the form y = mx + b, or leave it as written. The attached graph, has bot, and they overlap.
y+4=2/5(x−3)
or
y = (2/5)x-5.2
