All categories

3 years ago

Can somebody plz help answer these questions correctly! (only if u know it) thanks!!<3

Mathematics

2 answers:

TEA [102]3 years ago

7 0

Answer:

18-Yes 19-No 20-yes 21- yes

Step-by-step explanation:

1 to 4, 5 to 20

Yes, this is correct

WE can multiply 1*5 and 4*5 to get 5 to 20

Wrong

3 to 11, 1 to 3 isn't correct

For example, if we were to divide 3 by 3 to get one, 11/3 is 2. (6)

So, no

2/3 is 2 to 3

14/21 is 14 to 21

If we multiply 2*7 and 3*7, we get 14 to 21

21 25 to 30 is equal to 35 to 42

They just added 7 to both numbers

if we divide ratio 1 by 5, we get 5:6

if we divide ratio 2 by 7 we get 5 to 6

gizmo_the_mogwai [7]3 years ago

4 0

18. Yes
19. No
20. Yes
21. I think so

You might be interested in

√5 percent of 5√5 = a. 0.05 b. 0.25 c. 0.5 d. 2.5 e. 25

Stels [109]

$\sqrt{5} \% \times 5\sqrt{5}=\frac{\sqrt{5}}{100} \times 5\sqrt{5}=\frac{5 \times \sqrt{25}}{100}=\frac{5 \times 5}{100}=\frac{25}{100}=0.25$

The answer is B. 0.25.

8 0

4 years ago

On a standardized exam, the scores are normally distributed with a mean of 165 and astandard deviation of 40. Find the z-score o

vladimir1956 [14]

The Z-score is calculated by the formula below

$\begin{gathered} z-score=\frac{(x-\mu)}{\sigma}_{} \\ \mu=\operatorname{mean} \\ \sigma=s\tan dard\text{ deviation} \\ x=\text{score} \end{gathered}$

Step 2: Substitute the given parameters in the formula

$\begin{gathered} z-\text{score}=\frac{145-165}{40} \\ Z=-\frac{20}{40} \\ Z=-\frac{1}{2} \\ Z=-0.5 \end{gathered}$

Hence, the z-score of a person who scored 145 on the exam is -0.5

8 0

2 years ago

Solve for r -4(r+6)= -49

tatiyna

Answer: r= 25/3

Step-by-step explanation:

r-4(r+6)=-49 distribute the 4

r-4r-24=-49 combine like terms

-3r-24=-49 add 24 to both sides

-3r=-25 divide by -3

r= 25/3 answer

7 0

4 years ago

Expand $\left(x^2 \frac{1}{x}\right)^3$. (Write the terms with higher degree first, so for example an $x^2$ term would come befo

Ilya [14]

Answer:

$x^6+3x^3+3+\dfrac{1}{x^3}$

Step-by-step explanation:

We can use the pascal triangle to find the coefficients of the expasion of the cube. It holds that

$(x^2 + \dfrac{1}{x})^3=(x^2)^3+3(x^2)^2\dfrac{1}{x}+3x^2(\dfrac{1}{x})^2+(\dfrac{1}{x})^3\\\\=x^6+3x^4\dfrac{1}{x}+3x^2\dfrac{1}{x^2}+\dfrac{1}{x^3}\\\\=x^6+3x^3+3+\dfrac{1}{x^3}$

4 0

4 years ago

Please answer asap!!!

Luba_88 [7]

Answer:

The triangles are realated because there the same size so the triangles are equal

Step-by-step explanation:soory if i did not help

4 0

3 years ago