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rjkz [21]
2 years ago
15

Three numbers are in the ratio 1:3:5 and their sum is 270. find the largest number.

Mathematics
2 answers:
Sphinxa [80]2 years ago
8 0

Answer:

<u>150</u>

Step-by-step explanation:

Let :

⇒ The numbers can be denoted as <u>x</u>, <u>3x</u>, and <u>5x</u>

<u />

=============================================================

Solving :

⇒ It mentions their sum is 270

⇒ x + 3x + 5x = 270

⇒ 9x = 270

⇒ x = 30

=============================================================

Largest number :

⇒ 5x

⇒ 5(30)

⇒ <u>150</u>

kakasveta [241]2 years ago
4 0

<u>Answer</u><u> </u><u>:</u>

  • Largest number is 150.

<u>Step</u><u> </u><u>by</u><u> step</u><u> explaination</u><u> </u><u>:</u>

Here we have been given with the ratio of three numbers that is 1 : 3 : 5. So let us assume a common factor for them , we are assuming it as y.

Therefore,

  • First number = 1 → 1 × y = 1y
  • Second number = 3 → 3 × y = 3y
  • Third number = 5 → 5 × y = 5y

Sum of them is 270 :

>> 1y + 3y + 5y = 270

>> 4y + 5y = 270

>> 9y = 270

>> y = 270 / 9

>> y = 90 / 3

>> y = 30

Henceforth, value of y is 30.

★ Finding out first number :-

>> First number = 1y

>> First number = 1 × 30

>> First number = 30

★ Finding out second number :-

>> Second number = 3y

>> Second number = 3 × 30

>> Second number = 90

★ Finding out third number :-

>> Third number = 5y

>> Third number = 5 × 30

>> Third number = 150

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