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2 years ago

What is the square root of 10, and 9?

Mathematics

2 answers:

pantera1 [17]2 years ago

7 0

The answer is 3 your welcome ;)

Orlov [11]2 years ago

3 0

The answer is 3 and 3.16227766017

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Can you answer the attached question which includes the options to answer?

Gekata [30.6K]

2 and 4 are both correct statements.

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3 years ago

in order to prepare for building a brick patio, a rectangle measuring 8 feet by 10 feet must be marked off, then the dirt dug ou

Gala2k [10]

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3 years ago

Which of the following is the equation for the graph shown?a. x^2/144+y^2/95=1b. x^2/144-y^2/95=1c. x^2/95+y^2/144=1d. x^2/95-y^

Andrews [41]

e follSOLUTION

Given the question in the image, the following are the solution steps to answer the question

STEP 1: Write the general equation of an ellipse

$\frac{\mleft(x-h\mright)^2}{a^2}+\frac{(y-h)^2}{b^2^{}}=1$

STEP 2: Identify the parameters

the length of the major axis is 2a

the length of the minor axis is 2b

$\begin{gathered} 2a=24,a=\frac{24}{2}=12 \\ 2b=20,b=\frac{20}{2}=10 \end{gathered}$

STEP 3: Get the equation of the ellipse

$\begin{gathered} By\text{ substitution,} \\ \frac{(x-h)^2}{a^2}+\frac{(y-h)^2}{b^2}=1 \\ \frac{(x-0)^2}{12^2}+\frac{(y-0)^2}{10^2}=1=\frac{x^2}{144}+\frac{y^2}{100}=1 \end{gathered}$

STEP 4: Pick the nearest equation from the options,

Hence, the equation of the ellipse in the image is given as:

$\frac{x^2}{144}+\frac{y^2}{95}=1$

OPTION A

8 0

1 year ago

PLEASE HELP MY GROUP

Hoochie [10]

A=1007.27

B=2895.29

C=≈2714.34

D=111.84

6 0

3 years ago

Read 2 more answers

Please answer this question now

Rashid [163]

Answer:

Step-by-step explanation:

To solve problems like this, always recall the "Two-Tangent theorem", which states that two tangents of a circle are congruent if they meet at an external point outside the circle.

The perimeter of the given triangle = IK + KM + MI

IK = IJ + JK = 13

KM = KL + LM = ?

MI = MN + NI ?

Let's find the length of each tangents.

NI = IJ = 5 (tangents from external point I)

JK = IK - IJ = 13 - 5 = 8

JK = KL = 8 (Tangents from external point K)

LM = MN = 14 (Tangents from external point M)

Thus,

IK = IJ + JK = 5 + 8 = 13

KM = KL + LM = 8 + 14 = 22

MI = MN + NI = 14 + 5 = 19

Perimeter = IK + KM + MI = 13 + 22 + 19 = 54

4 0

3 years ago